我正在使用JPA 2.0。 Hibernate 4.1.0.Final和Java 6.如何从以下psuedo-SQL编写JPA查询?
select max(e.dateProcessed) from Event e where e.org = myOrg
我的域对象如下所示:
@GenericGenerator(name = "uuid-strategy", strategy = "org.mainco.subco.core.util.subcoUUIDGenerator")
@Entity
@Table(name = "sb__event",
uniqueConstraints = { @UniqueConstraint(columnNames={"EVENT_ID"}) }
)
public class Event
{
@Id
@Column(name = "ID")
@GeneratedValue(generator = "uuid-strategy")
private String id;
@ManyToOne(fetch = FetchType.LAZY, cascade = {CascadeType.REMOVE})
@JoinColumn(name = "ORGANIZATION_ID", nullable = false, updatable = true)
private Organization org;
@Column(name = "DATE_PROCESSED")
@NotNull
private java.util.Date dateProcessed;
我知道CriteriaBuilder.greatest参与其中,但我无法弄清楚如何编写查询。这将返回与组织匹配的所有事件对象,但这就是我已经获得的。
final CriteriaBuilder builder = m_entityManager.getCriteriaBuilder();
final CriteriaQuery<Event> criteria = builder.createQuery(Event.class);
final Root<Event> event = criteria.from(Event.class);
criteria.select(event);
criteria.where(builder.equal(Event.get("org"), org));
results.addAll(m_entityManager.createQuery(criteria).getResultList());
答案 0 :(得分:27)
有两种方法,一种使用JPQL,另一种使用条件查询 JPQL很简单:
em.createQuery("select max(e.dateProcessed) from Event e where e.org = :myOrg")
.setParameter("myOrg", myOrg)
.getSingleResult();
使用您可能拥有的标准时:
CriteriaBuilder qb = em.getCriteriaBuilder();
CriteriaQuery<Number> cq = qb.createQuery(Number.class);
Root<Event> root = cq.from(Event.class);
cq.select(qb.max(root.get("dateProcessed")));
cq.where(qb.equal(Event.get("org"), qb.parameter(MyOrgType.class, "myOrg")));
em.createQuery(cq).setParameter("myOrg", myOrg).getSingleResult();
答案 1 :(得分:0)
使用JPQL和CriteriaBuilder
CriteriaBuilder cb = getEntityManager().getCriteriaBuilder();
javax.persistence.criteria.CriteriaQuery cq= getEntityManager().getCriteriaBuilder().createQuery();
Root<T> c = cq.from(getEntityClass());
cq.select(cb.max(c.get("id")));