我正在尝试播种父表和子表。播种父母工作正常,但我不知道播种孩子的语法。请帮忙。
Contact.delete_all
Customer.delete_all
b=[]
c=[]
b[0]=[1231215,'Jeremy', 'G', '9177477337',
'jt@gmail.com', 'Central Ave', 'Rockaway', 'NY', ' 12291', '76 Son Court',
'ft lauderdale','Florida', '32423', '1', '0', '1', '1', '1', '1', '0', '0', '1', '0', '9.95',
'Honda', '2012', 'Civic', '2.4 Turbo', 'Special', '1J474GFGDHDH8883334D0','fart monkey trap']
b[1]=[46545465,'Se', 'Wof', '521428788',
'steven.j.wolfman@gmail.com', '13 NE 17 Street', 'broward', 'FL', ' 32222', '13 NE 17 Street',
'boca','Florida', '32222', '0', '0', '1',
'0', '0', '1', '1',
'1', '1', '1', '19.95',
'Ford', '2012', 'Taurus', '4.0', 'Faster', '3458GDHD3YU34D0','it smells']
c[0]=[5112432709,'jg@gmail.com']
c[1]=[4326546423,'sw@gmail.com']
c[2]=[6614328902,'jt@gmail.com']
i=0
while i<2 do
@customer=Customer.create(
:uid=>b[i][0],
:fname=>b[i][1],
:lname=>b[i][2],
:devphone=> b[i][3],
:email=>b[i][4],
:address=>b[i][5],
:city=>b[i][6],
:state=>b[i][7],
:zip=>b[i][8],
:baddress=>b[i][9],
:bcity=>b[i][10],
:bstate=>b[i][11],
:bzip=>b[i][12],
:roadass=>b[i][13],
:crisisass=>b[i][14],
:autocrash=>b[i][15],
:emergencyass=>b[i][16],
:remotediag=>b[i][17],
:carfind=>b[i][18],
:familytrack=>b[i][19],
:lowbatt=>b[i][20],
:towalerts=>b[i][21],
:monthlycost=>b[i][22],
:Make=>b[i][23],
:Year=>b[i][24],
:Model=>b[i][25],
:Engine=>b[i][26],
:VehicleSystem=>b[i][27],
:vinnum=>b[i][28],
:signupdate=>b[i][29],
:password=>b[i][30],
)
@customer.id=(1000000+i)
print "\n#{@customer.id}\n"
到目前为止,代码工作正常。当我在接下来的5行中添加代码时,代码不起作用。
Contact.create(
:customer_id=>@customer
:contactmethod=>"sms",
:contacttype=>c[i][0],
:dateadded=>"5-1-2013",
)
i+=1
end
这是我在运行db:seed时遇到的错误: 耙子流产了!对于#
,未定义的方法“联系”这是客户群
class Customer < ActiveRecord::Base
attr_accessible :Engine, :Make, :Model, :VehicleSystem, :Year, :address, :autocrash, :baddress, :bcity, :bstate, :bzip, :carfind, :city, :crisisass, :devphone, :email, :emergencyass, :familytrack, :fname, :lname, :lowbatt, :monthlycost, :password, :remotediag, :roadass, :signupdate, :state,:stolenveh, :towalerts, :uid, :vinnum, :zip
validates :email, :address,:fname, :lname, :password, :state, :uid, :zip, :presence => true
has_many :Contacts
end
这是联络基地
class Contact < ActiveRecord::Base
attr_accessible :contactmethod, :contacttype, :customer_id, :dateadded
validates :contactmethod, :contacttype, :customer_id, :presence => true
belongs_to :Customer
end
答案 这个问题的答案是你不能要求提供customer_id。因此,您只需通过删除:customer_id:
来修改验证 class Contact < ActiveRecord::Base
attr_accessible :contactmethod, :contacttype, :customer_id, :dateadded
validates :contactmethod, :contacttype, :presence => true
belongs_to :Customer
end
答案 0 :(得分:2)
首先不要用预先设置@
符号的变量命名变量,例如控制器和视图中的变量,seed.rb既不是那些东西。
其次,你使文件很难理解,试着简化它,例如。
Contact.delete_all
Customer.delete_all
customer1 = Customer.create(
# all of customer 1's details here
)
contact_for_customer_1 = Contact.create(
customer_id: customer1.id,
# customer 1's contact details
)
customer2 = Customer.create(
# all of customer 2's details here
)
contact_for_customer_2 = Contact.create(
customer_id: customer2.id,
# customer 2's contact details
)
这将有效且易于理解。您已将所有客户详细信息都放入文件中,因此您可以很好地将其详细说明。无需将详细信息存储在一个数组中,然后从那里构建客户,只需更详细地说明。
答案 1 :(得分:0)
这个问题的答案是您不能要求客户ID存在。因此,您只需通过删除:customer id:
来修改验证 class Contact < ActiveRecord::Base
attr_accessible :contactmethod, :contacttype, :customer_id, :dateadded
validates :contactmethod, :contacttype, :customer_id, :presence => true
belongs_to :Customer
end