Question

我想做以下事情。我输入值并点击提交。如果该值超出范围0和299，则保存文本＆＃39; blabla＆＃39;进入变量$ error。如果它在0和299的范围内，则将值更新为MySQL表（row-SkinID）; 这是我尝试过的，没有用的。这是我的HTML表单：

<form action="skinid.php" method="POST">
                            <!--<fieldset class="textarea-field">
                                <textarea title="Message">Message</textarea>
                            </fieldset>-->
<br>
                            <fieldset>
                                <span class="ico user-ico"></span>
                                <input name="skinid" onkeypress="return isNumberKey(event)" type="text" class="field" value="Enter new Skin ID. (-2000$)" title="Enter new Skin ID. (-2000$)" />
                            </fieldset>
                            <center><input type="submit" class="submit btn blue-btn" value="Update" /></center>
                        </form>
  <?php $_SESSION['skinid'] = $_POST['skinid']; ?>

这是skinid.php文件：

<?php
session_start();
$newskinid = $_SESSION['skinid'];
if($newskinid < '0' || $newskinid > '299'){$error = 'The Skin ID must be in the range of 0 and 299.';}
else {
$con=mysqli_connect("localhost","USERNAME","PASSWORD","DB-NAME");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }
mysqli_query($con,"UPDATE users SET SkinID=$newskinid
WHERE Username='$_SESSION[user]'");
mysqli_close($con);}
?>

Answer 1

尝试skinid.php：

<?php
session_start();
$_SESSION['skinid'] = $_POST['skinid']; 
$newskinid = $_SESSION['skinid'];
if($newskinid < '0' || $newskinid > '299') {
    echo 'The Skin ID must be in the range of 0 and 299.';
}
else {
    echo 'dhgj';
}
?>
<form method="post">

<br>
<fieldset>
    <span class="ico user-ico"></span>
    <input name="skinid" onkeypress="return isNumberKey(event)" type="text" class="field" value="Enter new Skin ID. (-2000$)" title="Enter new Skin ID. (-2000$)" />
</fieldset>
<center><input type="submit" class="submit btn blue-btn" value="Update" /></center>
</form>

Answer 2

除非第一个代码示例也来自skinid.php，否则在HTML表单中，您的$_POST['skinid']为空，因此在skinid.php中，您的$_SESSION['skinid']也将为空。

相反，在skinid.php中使用： $newskinid = $_POST['skinid'];

无法制作表格。

2 个答案: