我有一个SQL,它将id,开始日期和结束日期作为参数。然后,我确定那些受where子句限制的。但是,我还需要对未考虑数据参数的相同列进行求和,并计算特定驱动程序的总数。例如:
SELECT DISTINCT
PMTS.VolunteerId,
PMTS.ChargeRate,
SUM(
CASE [Type]
WHEN 418 THEN Amount
ELSE 0
END
) AS DriverMileage,
SUM(
CASE [Type]
WHEN 1000 THEN Amount
ELSE 0
END
) AS GPMileage,
SUM(
CASE [Type]
WHEN 1001 THEN Amount
ELSE 0
END
) AS Reimbursements,
SUM(
CASE [Type]
WHEN 1002 THEN Amount
ELSE 0
END
) AS MobilePhoneCharges,
SUM(Mileage) AS TotalMileageWeek,
B.TotalMileage,
VOLS.Address1,
VOLS.Address2,
VOLS.Town,
ISNULL(VOLS.Surname, '') + ', ' + ISNULL(VOLS.Forename, '') AS SurnameForename ,
ISNULL(VOLS.County, '') + ' ' + ISNULL(VOLS.PostCode, '') AS CountyPostcode
FROM dbo.vVolunteerPayments PMTS
INNER JOIN dbo.vVolunteers VOLS ON PMTS.VolunteerId = VOLS.VolunteerID
--total mileage
INNER JOIN (select VolunteerId, sum(Mileage) as TotalMileage
FROM dbo.vVolunteerPayments GROUP BY VolunteerId) b ON
b.VolunteerID=PMTS.VolunteerId
WHERE
PMTS.VolunteerId = @volunteerid
AND
PMTS.PaymentEventID = 0
AND
PMTS.DateCreated BETWEEN @sd AND @ed
GROUP BY
PMTS.VolunteerId
,Address1
,Address2
,Town
,County
,PostCode
,Surname
,Forename
,B.TotalMileage
,PMTS.ChargeRate
所以SUM(Mileage)As MileageTotal忽略where子句
答案 0 :(得分:1)
试试这个:
Select
a.Name,
SUM(Mileage) As MileageWeek,
SUM(Mileage) As MileageTotal,
b.TotMiles
FROM <table> a
JOIN (select name,sum(Mileage) as TotMiles
FROM <table> GROUP By name) b ON b.name=a.name
WHERE
Journey.DateCreated BETWEEN @startdate AND @enddate
将< table >
替换为您的实际牌桌名称(旅程 ???)
答案 1 :(得分:0)
消除where
子句并进行条件求和:
Select Name,
SUM(case when Journey.DateCreated BETWEEN @startdate AND @enddate then Mileage
else 0
end) As MileageWeek,
SUM(Mileage) As MileageTotal
from Journey
我还在from
条款中添加了(可能是你意外地将其遗漏了)。
SUM(
CASE [Type]
WHEN 418 THEN Amount
ELSE 0
END
) AS DriverMileage,
到
sum(case when [type] = 418 and PMTS.DateCreated BETWEEN @sd AND @ed then amount
else 0
end) as DriverMileage
您可能需要在where
子句中包含更多条件 - 我不确定您想要的总数。