选择名称相似的文件

Question

我正在搜索允许选择具有相似名称的多个文件的脚本。 我有10个文件：

1. hello.myapp-1.apk
2. hello.myapp-2.apk
3. hello.myapp-3.apk
4. hello.myapp-4.apk
5. other.ot
6. ...
7. ...
8. ...
9. ... 10 ....

我想从hello.myapp-1.apk中选择文件到hello.myapp-4.apk。可以只使用这样的一行代码吗？

File su6 = new File("/dir/app/hello.myapp-*.apk");

Answer 1

File dir = new File("/dir/app/");
File [] files = dir.listFiles(new FilenameFilter() {
    @Override
    public boolean accept(File dir, String name) {
        return name.startsWith("hello.myapp-") && name.endsWith(".apk");
    }
});

for (File file : files) {
    //do stuff with file
}

Answer 2

您可以这样做：

File[] result = f.listFiles(new FilenameFilter() {
    public boolean accept(File dir, String name) {
      return name.startsWith("hello.myapp-");//or use contains, regex/matcher etc
    }
});

Answer 3

for (int i=0; i<5; i++)
  File su6 = new File("/dir/app/hello.myapp-" + i + ".apk");