Question

from datetime import datetime

class sms_store:
    store = []
    read = []
def add_new_arrival(self,number,time,text):
    sms_store.read.append(len(sms_store.store))
    sms_store.store.append(("From: {}, Recieved: {}, Msg: {}".format(number,time,text)))
def delete(self,i):
    try:
        del sms_store.store[i]
    except IndexError:
        print("Index is out of range. Cannot delete")
def message_count(self):
    return print("Amt of messages in inbox: {}".format(len(sms_store.store)))
def viewall(self):
    print(sms_store.store)
def get_unread_indexes(self):
    #### ###################################I need help for this method.
def get_message(self,i)
    print(sms_store.store[i])
### tests ####
time = datetime.now().strftime('%H:%M:%S')
my_inbox = sms_store() #instantiate an object 'store' for class
my_inbox.add_new_arrival("12345",time,"Hello how are you?") #instance of store object
my_inbox.add_new_arrival("1111111",time,"BYE BYE BYE")
my_inbox.viewall()
my_inbox.msgcount()

感谢您查看此内容。

这就是我需要做的事情：

my_inbox.add_new_arrival()

添加新邮件时，其has_been_viewed状态设置为False。

my_inbox.get_unread_indexes()

返回所有尚未查看的SMS消息的索引列表

my_inbox.get_message(i)**

为消息[i]返回（from_number，time_arrived，text_of_sms）也将其状态更改为“已被查看”。如果位置i没有消息，则返回无

请帮我解决上述方法！？

非常感谢你！

Answer 1

嗨，我稍稍调整了你的代码，我想我之前在＃34;如何思考计算机科学家书＆＃34;，希望它适合你。

updateEQAnimation(position);

和

from datetime import datetime

然后

class SMS_store:

Answer 2

为什么不在类中添加另一个名为unread的列表。更改add_new_arrival以将邮件添加到未读。

然后在get_message方法下将指定的消息从未读移动到读取。

最后，您的get_unread方法只列出未读列表的索引。

Answer 3

使用类和方法的Python SMS存储程序-has_been_viewed状态

import time
class SMS_store:
    def __init__(self):
        self.inbox = []

    def add_new_arrival(self, from_number, text_of_sms,read_status = False):
        number = str(from_number)
        time_received = time.strftime("%D %T")
        self.inbox.append([time_received, number, text_of_sms, read_status])

    def message_count(self):
        return "There are {0} messages in your Inbox".format(len(self.inbox))

    def get_unread_indexes(self):
        unread = []
        for index, message in enumerate(self.inbox):
            if False in message:
                unread.append(index)
        return "Unread Messages in:", unread

    def get_message(self, index):
        message = self.inbox[index]
        message[3] = "Read"
        return message[ : 3]

    def delete(self, index):
        del self.inbox[index]
        return "Deleted Message", index

    def clear(self):
        self.inbox = []
        return "Empty Inbox"

Python短信存储程序使用类和方法 - has_been_viewed状态

3 个答案: