我使用WCF REST服务模板40(CS)创建了一个网站,它有一个这样的服务方法:
[WebInvoke(UriTemplate = "CTNotification", Method = "POST", ResponseFormat = WebMessageFormat.Json,
RequestFormat = WebMessageFormat.Json)]
public string CTNotification(Stream contents)
我怎样才能将json传递给它?我不能将服务参数作为字符串,因为客户端将发送json作为流。如何使用C#对内容类型为= application / json
的此服务方法进行调用此致 Asif Hameed
答案 0 :(得分:0)
我不确定你是在同步还是同步,但这里是如何传递你的args。实施可能会根据客户的需求而有所不同
HttpWebRequest httpWReq = (HttpWebRequest)WebRequest.Create(ServiceAddress + "CTNotification/");
//parameters
byte[] data = Encoding.UTF8.GetBytes(jsonString);
httpWReq.Method = "POST";
httpWReq.ContentType = "application/x-www-form-urlencoded";
httpWReq.ContentLength = data.Length;
httpWReq.Timeout = 1000;
using (Stream newStream = httpWReq.GetRequestStream())
{
newStream.Write(data, 0, data.Length);
}