编组XML Go XMLName + xmlns

时间:2013-04-24 21:05:01

标签: xml go marshalling

我正在尝试实现以下XML输出

<?xml version="1.0" encoding="UTF-8"?>

<CreateHostedZoneRequest xmlns="https://route53.amazonaws.com/doc/2012-12-12/">
   <Name>DNS domain name</Name>
   <CallerReference>unique description</CallerReference>
   <HostedZoneConfig>
      <Comment>optional comment</Comment>
   </HostedZoneConfig>
</CreateHostedZoneRequest>

我有以下输出非常接近的XML但是我无法编码到CreateHostedZoneRequest

  

的xmlns =“https://route53.amazonaws.com/doc/2012-12-12/

package main

import "fmt"
import "encoding/xml"

type ZoneRequest struct {
  Name            string
  CallerReference string
  Comment         string `xml:"HostedZoneConfig>Comment"`
}

var zoneRequest = ZoneRequest{
  Name:            "DNS domain name",
  CallerReference: "unique description",
  Comment:         "optional comment",
}

func main() {
  tmp, _ := createHostedZoneXML(zoneRequest)
  fmt.Println(tmp)
}

func createHostedZoneXML(zoneRequest ZoneRequest) (response string, err error) {
  tmp := struct {
    ZoneRequest
    XMLName struct{} `xml:"CreateHostedZoneRequest"`
  }{ZoneRequest: zoneRequest}

  byteXML, err := xml.MarshalIndent(tmp, "", `   `)
  if err != nil {
    return "", err
  }
  response = xml.Header + string(byteXML)
  return
}

http://play.golang.org/p/pyK76VPD5-

如何将xmlns编码为CreateHostedZoneRequest?

2 个答案:

答案 0 :(得分:5)

我有一个类似的问题。 Unmarshal方法(http://golang.org/pkg/encoding/xml/#Unmarshal)的文档包含:

  

如果XMLName字段具有“name”或“namespace-URL name”形式的关联标记,则XML元素必须具有给定名称(以及可选的名称空间),否则Unmarshal将返回错误。

在struct标签中使用“namespace-URL name”:

type ZoneRequest struct {
    XMLName  xml.Name `xml:"https://route53.amazonaws.com/doc/2012-12-12/ CreateHostedZoneRequest"`
}

应该产生:

<CreateHostedZoneRequest xmlns="https://route53.amazonaws.com/doc/2012-12-12/">

答案 1 :(得分:4)

你可以这样做,这可能不是最优雅的解决方案,但似乎有效

Playground link

type ZoneRequest struct {
    Name            string
    CallerReference string
    Comment         string `xml:"HostedZoneConfig>Comment"`
    Xmlns           string `xml:"xmlns,attr"`
}

var zoneRequest = ZoneRequest{
    Name:            "DNS domain name",
    CallerReference: "unique description",
    Comment:         "optional comment",
    Xmlns:           "https://route53.amazonaws.com/doc/2012-12-12/",
}

<?xml version="1.0" encoding="UTF-8"?>

<CreateHostedZoneRequest xmlns="https://route53.amazonaws.com/doc/2012-12-12/">
   <Name>DNS domain name</Name>
   <CallerReference>unique description</CallerReference>
   <HostedZoneConfig>
      <Comment>optional comment</Comment>
   </HostedZoneConfig>
</CreateHostedZoneRequest>