GNU Sed REGEX查找并更改字符串（无替换）

Question

我有以下文字：

11 Cherrywood Rise Ashford Kent TN25 4QA United Kingdom N B BONE 02/12 387
Bisham village Bisham Buckinghamshire SL7 1RR United Kingdom Neil Noakes 06/13 488
6 Kynaston Road London London N16 0EX United Kingdom MR N P SALTMARSH 04/13 907
116 Long Acre London London WC2E 9SU United Kingdom Lorna J Gradden 11/14 415

如何使用sed匹配日期“mm / yy”格式并更改为“| mm / yy |”

赞：11 Cherrywood Rise Ashford Kent TN25 4QA United Kingdom N B BONE|02/12|387

谢谢！

Answer 1

这对你有用吗？

sed -r 's# ([0-9]{2}/[0-9]{2}) #|\1|#' file

Answer 2

示例1

cat t.txt | sed -E 's/([0-9]{2}\/[0-9]{2})/|\1|/g'

11 Cherrywood Rise Ashford Kent TN25 4QA United Kingdom N B BONE（02/12）387 Bisham village Bisham Buckinghamshire SL7 1RR英国Neil Noakes（06/13）488 6 Kynaston Road London London N16 0EX United Kingdom MR N P SALTMARSH（04/13）907 116英亩伦敦伦敦WC2E 9SU英国Lorna J Gradden（11/14）415

或

sed -E 's/([0-9]{2}\/[0-9]{2})/|\1|/g' t.txt