Question

我的FQL为UID返回非法字符。这是我的FQL。 select uid,books from user where uid in (select uid2 from friend where uid1=me())。我正在使用PHP SDK，我正在获取像1.0000008018280E+14这样的ID（两者之间有'E'in）。我总共600个联系人中的大约400个显示UID。我尝试指向facebook.com/1.0000008018280E+14，返回 304页面未找到错误。我正在使用的代码是

  $fql_query_url = 'https://graph.facebook.com/'.'fql?q=select+uid,books+from+user+where+uid+in(select+uid2+from+friend+where+uid1=me())'.'&access_token='.$_GET['access'];
   $fql_query_result = file_get_contents($fql_query_url);
   $fql_query_obj = json_decode($fql_query_result, true)

  // display results of fql query
echo '<pre>';
print_r($fql_query_obj);
echo '</pre>';

Answer 1

根据How to get around or make PHP json_decode not alter my very large integer values?，您可以这样做：

<?php
$fql_query_url = 'https://graph.facebook.com/'.'fql?q=select+uid,books+from+user+where+uid+in(select+uid2+from+friend+where+uid1=me())'.'&access_token='.$_GET['access'];
$fql_query_result = file_get_contents($fql_query_url);
$fql_query_result = preg_replace('/:\s*(\-?\d+(\.\d+)?([e|E][\-|\+]\d+)?)/', ': "$1"', $fql_query_result);
$fql_query_obj = json_decode($fql_query_result, true);

echo '<pre>';
print_r($fql_query_obj);
echo '</pre>'; 
?>

或，如Handling big user IDs returned by FQL in PHP

所示

<?php
$fql_query_url = 'https://graph.facebook.com/'.'fql?q=select+uid,books+from+user+where+uid+in(select+uid2+from+friend+where+uid1=me())'.'&access_token='.$_GET['access'];
$fql_query_result = file_get_contents($fql_query_url);
$fql_query_obj = json_decode(preg_replace('/("\w+"):(\d+)/', '\\1:"\\2"', $fql_query_result), true);

echo '<pre>';
print_r($fql_query_obj);
echo '</pre>'; 
?>

Facebook FQL中的非法字符

1 个答案: