Question

我必须查询此表：

symbol    time
------    ----------
aaa       2013-04-18 09:10:28.000    
bbb       2013-04-18 09:10:27.000    
aaa       2013-04-18 09:10:27.000    
bbb       2013-04-18 09:10:26.000

对于具有最长时间值的所有不同符号，我需要一行。我如何编写linq查询？

提前致谢，

Answer 1

按符号对行进行分组，然后从每个组项目中选择max time （表是上下文中的数据库表名称）：< / p>

from r in Table
group r by r.symbol into g
select g.OrderByDescending(x => x.time).First()

与方法语法相同：

Table.GroupBy(r => r.symbol)
     .Select(g => g.OrderByDescending(x => x.time).First());

Answer 2

试试这个

var q = MyTable.GroupBy(x => x.symbol )
               .Select(g => g.OrderByDescending(i => i.time).First());

或像这样使用max

 var data = from r in MyTable
                   group r by r.symbol into g
                   select new { name= g.Key, data= g.Max(a=>a.time) };

Answer 3

我实际上会用。

void Main()
{
    var set = new [] {
        new Foo{A = "aaa", B = 1},
        new Foo{A = "bbb", B = 2},
        new Foo{A = "aaa", B = 3},
        new Foo{A = "bbb", B = 4},
    };

    var result = from x in set
                group x.B by x.A into g
                select new {id = g.Key, biggest = g.Max()};

    Console.WriteLine(result);
}

Answer 4

你可以在Linq -

中使用lambda表达式

var result= (from li in List.Distinct().OrderByDescending(x => x.time)
                       select li).FirstOrDefault();

Linq distinct＆amp; amp;最大

4 个答案: