Question

<?php  $student = array(
     1 => array(
         "firstname" => "first",
         "name" => "first",
         "group" => "grp01",
         "score" => array(
             "ASP" => 86,
             "PHP" => 79,
             "JAVA" => 72,
             "HTML" => 96,
             "JAVASCRIPT" => 98,
             "VBNET" => 66
         )
     ),
     2 => array(
         "firstname" => "second",
         "name" => "second",
         "group" => "grp01",
         "score" => array(
             "ASP" => 80,
             "PHP" => 70,
             "JAVA" => 71,
             "HTML" => 92,
             "JAVASCRIPT" => 90,
             "VBNET" => 78
         )
     ),
     3 => array(
         "firstname" => "third",
         "name" => "third",
         "group" => "grp02",
         "score" => array(
             "ASP" => 88,
             "PHP" => 88,
             "JAVA" => 89,
             "HTML" => 96,
             "JAVASCRIPT" => 98,
             "VBNET" => 71
         )
     )  ); ?>

<?php

foreach($student as $std) {
    foreach($std as $key => $p){
        echo $std[$key];
    } } ?>

我正在尝试打印回应每个学生他们的平均分数，但现在我被卡住我得到一个关于数组到字符串转换的警告可以有人给我一些提示我怎么想我做我的循环。

Answer 1

你正在迭代错误的数组，一旦进入每个学生，你必须迭代“得分”，如果不是你试图将得分数组转换为字符串：

foreach($student as $std) {
    foreach($std["score"] as $language => $score) {
        echo $score;
    }
}

Answer 2

使用PHP函数计算每个学生的平均值，四舍五入到两位数：

foreach($student as $std) {

    $avg = round(array_sum($std['score']) / count($std['score']), 2);
    echo $std['name']. ": $avg <br />";
}

看到它有效：http://codepad.viper-7.com/RBINCd

Answer 3

当您尝试回显数组的“得分”部分时，会出现错误。因为它本身就是一个数组，所以不能用这种方式回声。您将需要另一个循环来累加分数，然后得到它之外的平均值。

有些事情：

foreach($student as $std) {
    foreach($std as $key => $p){

        if ( $key === 'score'){

            $avg = 0;

            foreach( $p as $score){
              $avg += $score;
            }

            $avg = ($avg/size_of($p));
         }

    } 
}

PHP警告数组到数组键内的字符串转换循环

3 个答案: