我目前想要使用w3schools图片上传代码,直到我找到一段时间我编码的那个。无论如何:
<?php
$allowedExts = array("gif", "jpeg", "jpg", "png");
$extension = end(explode(".", $_FILES["file"]["name"]));
if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/jpg")
|| ($_FILES["file"]["type"] == "image/png"))
&& ($_FILES["file"]["size"] < 20000)
&& in_array($extension, $allowedExts))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>";
if (file_exists("upload/" . $_FILES["file"]["name"]))
{
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
}
else
{
echo "Invalid file";
}
?>
基本上我想要发生的是当用户上传文件时,它将文件名重命名为$ username而不是原始名称,所以它只是username.png而不是我目前拥有的用户名-38474.png < / p>
任何帮助?
答案 0 :(得分:8)
move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]);
这行代码基本上将图像重命名为新位置:"upload/".$_FILES["file"]["name"]
,因此请将此行替换为:
move_uploaded_file($_FILES["file"]["tmp_name"], "upload/".$username.".".$extension);
答案 1 :(得分:0)
所以只需将不同的参数传递给move_uploaded_file
:
$extension = explode("/", $_FILES["file"]["type"]); //Use proper mime type here, $_FILES contents can be faked by remote user
move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $username.".".$extension[1]);