Question

以下是我试图回答的提示：

显示该经理的最低薪员工的经理编号和薪水（仅限） - 适当标记。不包括经理不详的员工的工资。在这里排除任何组，最低工资低于1000美元。先列出最低工资。

以下是我的EMPLOYEES表：

create table EMPLOYEES
    (EmpID    char(4)         unique Not null,
     Ename    varchar(10),
     Job      varchar(9),
     MGR      char(4),
     Hiredate date,
     Salary   decimal(7,2),
     Comm     decimal(7,2),
     DeptNo   char(2)         not null,
         Primary key(EmpID),
         Foreign key(DeptNo) REFERENCES DEPARTMENTS(DeptNo));


insert into EMPLOYEES values (7839,'King','President',null,'17-Nov-11',5000,null,10);
insert into EMPLOYEES values (7698,'Blake','Manager',7839,'01-May-11',2850,null,30);
insert into EMPLOYEES values (7782,'Clark','Manager',7839,'02-Jun-11',2450,null,10);
insert into EMPLOYEES values (7566,'Jones','Manager',7839,'02-Apr-11',2975,null,20);
insert into EMPLOYEES values (7654,'Martin','Salesman',7698,'28-Feb-12',1250,1400,30);
insert into EMPLOYEES values (7499,'Allen','Salesman',7698,'20-Feb-11',1600,300,30);
insert into EMPLOYEES values (7844,'Turner','Salesman',7698,'08-Sep-11',1500,0,30);
insert into EMPLOYEES values (7900,'James','Clerk',7698,'22-Feb-12',950,null,30);
insert into EMPLOYEES values (7521,'Ward','Salesman',7698,'22-Feb-12',1250,500,30);
insert into EMPLOYEES values (7902,'Ford','Analyst',7566,'03-Dec-11',3000,null,20);
insert into EMPLOYEES values (7369,'Smith','Clerk',7902,'17-Dec-10',800,null,20);
insert into EMPLOYEES values (7788,'Scott','Analyst',7566,'09-Dec-12',3000,null,20);
insert into EMPLOYEES values (7876,'Adams','Clerk',7788,'12-Jan-10',1100,null,20);
insert into EMPLOYEES values (7934,'Miller','Clerk',7782,'23-Jan-12',1300,null,10);

以下是我的疑问：

select empid, salary
from employees
where salary in
(select MIN(salary)
from employees
where empid in
(select empid
from EMPLOYEES
where JOB != 'manager'))
order by Salary asc;

结果只是经理以外的最低薪人士。我需要每位经理薪酬最低的工人，包括总统领导下的最低工资经理。

Answer 1

select empid, salary
from employees
where salary in
(select MIN(salary)
from employees
where empid in
(select empid
from EMPLOYEES
where JOB != 'manager'
 group by EmpID
 )
 and
 JOB != 'manager' and MGR is not null
 group by mgr
 )
order by Salary asc;

Answer 2

试试这个：

select MGR, MIN(salary)
from EMPLOYEES e
where Salary >= 1000 and MGR is not null
group by mgr
order by MIN(salary)

或者也许：

select MGR, MIN(salary)
from EMPLOYEES e
where  MGR is not null
group by mgr
having min(salary) >= 1000
order by MIN(salary)

声明“在这里排除任何团体的最低工资低于1000美元”对我来说并不清楚。

嵌套SQL聚合函数查询以获取每个管理器的最低付费员工：我的查询不起作用

2 个答案: