我有一个像
这样的示例文件stat1: sample: 0.0
stat2: sample: 0.0
stat3: sample: 349.7
stat1: sample: 0.0
stat2: sample: 0.0
stat3: sample: 349.7
stat1: sample: 0.0
stat2: sample: 0.0
stat3: sample: 349.7
我要做的是找到每个统计数据的最大值和平均值。
答案 0 :(得分:1)
如果您不介意使用Perl:
perl -lane '{ if(/(stat\d+)/) {
$m{$1} =$F[2] if $m{$1}<$F[2] || !$m{$_};
$s{$1}+=$F[2]; $c{$1}++
}} END{print "$_: $m{$_},".$s{$_}/$c{$_} for keys %c}' input
答案 1 :(得分:1)
awk '{
if (NF != 3) next
sum[$1] += $3;
if (cnt[$1]++ == 0) { max[$1] = $3; min[$1] = $3; }
if ($3 > max[$1]) max[$1] = $3
if ($3 < min[$1]) min[$1] = $3
}
END {
printf "%-8s %4s %8s %8s %8s\n", "Sample", "N", "Minimum", "Maximum", "Average"
for (key in sum)
{
printf "%-8s %4d %8.2f %8.2f %8.2f\n", key, cnt[key], min[key], max[key], sum[key]/cnt[key]
}
}' data-file
示例输出(来自问题中的数据,这是非常令人兴奋的):
Sample N Minimum Maximum Average
stat2: 3 0.00 0.00 0.00
stat1: 3 0.00 0.00 0.00
stat3: 3 349.70 349.70 349.70
此代码包括最小值和最大值;如果它是不需要的,它很容易删除。请注意,它会跳过数据文件中的空白行。
答案 2 :(得分:1)
使用awk关联数组非常简单:
meanmax.awk
# Skip empty lines
NF==0 { next }
# Keep a tally of number of elements and their sum
{ cnt[$1]++; sum[$1] += $3 }
# If max[$1] has not been defined or if it is smaller than $3
cnt[$1] == 1 || max[$1] < $3 {
max[$1] = $3
}
END {
for (k in sum)
print k, max[k], sum[k]/cnt[k]
}
像这样运行:
awk -f meanmax.awk infile
输出:
stat1: 0.0 0
stat2: 0.0 0
stat3: 349.7 349.7
或者如果在最初发布的输入上运行:
stat1: 18.0 10.3333
stat2: 45.0 16.6667
stat3: 239.7 89.4667
答案 3 :(得分:1)
如果您需要所有值的均值和最大值,您可以尝试这样的
awk '/sample:/ {s[$1] += $3; if(++n[$1]==1 || max[$1]<$3) max[$1] = $3}
END { for (i in s) print i" mean = "s[i]/n[i]", max = "max[i] }
' <<EOT
stat1: sample: 0.0
stat2: sample: 0.0
stat3: sample: 349.7
stat1: sample: 0.0
stat2: sample: 0.0
stat3: sample: 349.7
stat1: sample: 0.0
stat2: sample: 0.0
stat3: sample: 349.7
EOT
输出:
stat3: mean = 349.7, max = 349.7
stat1: mean = 0, max = 0.0
stat2: mean = 0, max = 0.0