我在这个面向对象的课程中,但我不知道该怎么做。我知道基本的基本原理但不是这样的。我被要求创建一个程序,将#的基数10转换为基数2,基数8和基数16.然后,在我们被要求将其从2,8,16转换回基数10.之后我收集了一些信息从其他网站,我实际上最终编辑了一点。 请帮忙! 我更喜欢它,如果你们真的帮助和编辑自己并将它发送给我,但如果这太多了,请尝试指导我,因为我不太了解Java。 到目前为止,我有:
import java.util.Scanner;
public class baseconverterr
{
public static void main(String[] args) {
// Read the conversion choice from the user
System.out.println("Choose 1 or 2 or 3:");
System.out.println("1: conversion from base 10 to base 2 ");
System.out.println("2: conversion from base 10 to base 8");
System.out.println("3: conversion from base 10 to base 16");
// do you want 1, 2 , or 3? you have your choice
Scanner in = new Scanner(System.in);
int choice = in.nextInt();
String string = in.nextLine();
// Read in the number to be converted and do the conversion
String output= "";
System.out.println("Please enter the number to be converted:");
int input = in.nextInt();
if (choice == 1)
// if the user chooses choice #1, it will convert from base 10 to base 2
output = Integer.toString(input, 2);
else if (choice == 2)
output = Integer.toString(input, 8);
// if the user chooses choice #2, it will convert from base 10 to base of 8
else if (choice == 3)
output = Integer.toString(input, 16);
// if the user chooses choice #3, it will convert from base 10 to base 16
else
System.out.println("invalid entry");
// everything else, it is invalid
System.out.println("final output=" + output);
// this prints the final output.
答案 0 :(得分:30)
对于十进制x(基数10),您可以分别使用二进制,八进制,十六进制转换
Integer.toString(x, 2)
,
Integer.toString(x, 8)
Integer.toString(x, 16)
。
然后将其转换为十进制,分别从二进制,八进制,十六进制转换
Integer.valueOf(binary_value, 2)
Integer.valueOf(octal_value, 8)
Integer.valueOf(hex_value, 16)
,请更改以下内容:
output = Integer.toString(input, 16) //replace 16 for hex, 8 for octal, 2 for binary
答案 1 :(得分:0)
使用此
if (choice == 1)
output = Integer.toString(input, 2);
else if (choice == 2)
output = Integer.toString(input, 8);
// if the user chooses choice #2, it will convert from base 10 to base of 8
else if (choice == 3)
output = Integer.toString(input, 16);
else
System.out.println("invalid entry");