Question

根据这个样本：

http://www.codeproject.com/KB/mobile/DeepCast.aspx

在发送小单元信息（MCC，MNC，towerid等）时，可以请求gps坐标（经度和纬度），包括范围

有人可以告诉我请求/发布到此地址的实际参数吗？

http://www.google.com/glm/mmap

可能是这样的

http://www.google.com/glm/mmap?mcc=xxx&mnc=xxx&towerid=xxx

我想知道我们会得到什么回应。

我观察过OpenCellid网站，他们提供了一些不错的API，但我也希望在谷歌地图中了解它（因为他们有更多完整的数据库）。

OpenCellID API

Answer 1

您可以使用Firefox使用的Google位置API（示例见http://www.mozilla.com/en-US/firefox/geolocation/），其中包含网址www.google.com/loc/json/。实际上，这是基于JSON的Web服务和最小的Perl示例，如下所示：

use LWP;

my $ua = LWP::UserAgent->new;
$ua->agent("TestApp/0.1 ");
$ua->env_proxy();

my $req = HTTP::Request->new(POST => 'https://www.google.com/loc/json');

$req->content_type('application/jsonrequest');
$req->content('{"cell_towers": [{"location_area_code": "8721", "mobile_network_code": "01", "cell_id": "7703", "mobile_country_code": "262"}], "version": "1.1.0", "request_address": "true"}');

# Pass request to the user agent and get a response back
my $res = $ua->request($req);

# Check the outcome of the response
if ($res->is_success) {
    print $res->content;
} else {
    print $res->status_line, "\n";
    return undef;
}

请注意，Google尚未正式将此API用于其他用途......

Answer 2

以下是使用

的示例

#!/usr/bin/python

country = 'fr'
#device = 'Sony_Ericsson-K750'
device = "Nokia N95 8Gb"
user_agent = 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'
mmap_url = 'http://www.google.com/glm/mmap'
geo_url = 'http://maps.google.com/maps/geo'

from struct import pack, unpack
from httplib import HTTP
import urllib2

def fetch_latlong_http(query):
    http = HTTP('www.google.com', 80)
    http.putrequest('POST', '/glm/mmap')
    http.putheader('Content-Type', 'application/binary')
    http.putheader('Content-Length', str(len(query)))
    http.endheaders()
    http.send(query)
    code, msg, headers = http.getreply()
    result = http.file.read()
    return result

def fetch_latlong_urllib(query):
    headers = { 'User-Agent' : user_agent }
    req = urllib2.Request(mmap_url, query, headers)
    resp = urllib2.urlopen(req)
    response = resp.read()
    return response

fetch_latlong = fetch_latlong_http

def get_location_by_cell(cid, lac, mnc=0, mcc=0, country='fr'):
    b_string = pack('>hqh2sh13sh5sh3sBiiihiiiiii',
                    21, 0,
                    len(country), country,
                    len(device), device,
                    len('1.3.1'), "1.3.1",
                    len('Web'), "Web",
                    27, 0, 0,
                    3, 0, cid, lac,
                    0, 0, 0, 0)

    bytes = fetch_latlong(b_string)
    (a, b,errorCode, latitude, longitude, c, d, e) = unpack(">hBiiiiih",bytes)
    latitude = latitude / 1000000.0
    longitude = longitude / 1000000.0

    return latitude, longitude

def get_location_by_geo(latitude, longitude):
    url = '%s?q=%s,%s&output=json&oe=utf8' % (geo_url, str(latitude), str(longitude))
    return urllib2.urlopen(url).read()

if __name__ == '__main__':
    print get_location_by_cell(20465, 495, 3, 262)
    print get_location_by_cell(20442, 6015)
    print get_location_by_cell(1085, 24040)
    print get_location_by_geo(40.714224, -73.961452)
    print get_location_by_geo(13.749113, 100.565327)

Answer 3

基于GeolocationAPI，以下是我的代码的一些部分：

import java.io.IOException;
import java.io.StringWriter;
import java.net.HttpURLConnection;
import java.net.URL;

//http://code.google.com/p/google-gson/
import com.google.gson.stream.JsonWriter;

...

/**
 * Requests latitude and longitude from Google.
 * 
 * @param gsmParams
 *            {@link GsmParams}
 * @return an {@link HttpURLConnection} containing connection to Google
 *         lat-long data.
 * @throws IOException
 */
public HttpURLConnection requestLatlongFromGoogle(GsmParams gsmParams)
        throws IOException {
    // prepare parameters for POST method
    StringWriter sw = new StringWriter();
    JsonWriter jw = new JsonWriter(sw);
    try {
        jw.beginObject();

        jw.name("host").value("localhost");
        jw.name("version").value("1.1.0");
        jw.name("request_address").value(true);

        jw.name("cell_towers");

        jw.beginArray().beginObject();

        jw.name("cell_id").value(gsmParams.getCid());
        jw.name("location_area_code").value(gsmParams.getLac());
        jw.name("mobile_network_code").value(gsmParams.getMnc());
        jw.name("mobile_country_code").value(gsmParams.getMcc());

        jw.endObject().endArray().endObject();
    } finally {
        try {
            jw.close();
        } catch (IOException ioe) {
        }
        try {
            sw.close();
        } catch (IOException ioe) {
        }
    }
    final String JsonParams = sw.toString();
    final String GoogleLocJsonUrl = "http://www.google.com/loc/json";

    // post request
    URL url = null;
    HttpURLConnection conn = null;
    url = new URL(GoogleLocJsonUrl);
    conn = (HttpURLConnection) url.openConnection();
    conn.setConnectTimeout((int) 30e3);
    conn.setReadTimeout((int) 30e3);

    conn.setDoOutput(true);
    conn.setRequestMethod("POST");
    conn.getOutputStream().write(JsonParams.getBytes());
    conn.getOutputStream().flush();
    conn.getOutputStream().close();
    int resCode = conn.getResponseCode();
    if (resCode == Http_BadRequest || resCode != Http_Ok) {
        throw new IOException(String.format(
                "Response code from Google: %,d", resCode));
    }
    return conn;
}

对象GsmParams只是一个包含GSM参数MCC，MNC，LAC，CID的Java bean。我认为你可以轻松创建一个同类课程。

获得连接后，您可以致电conn.getInputStream()并从Google地图获取结果。然后使用JsonReader解析数据...

Answer 4

Google位置API的新地点如下： https://developers.google.com/maps/documentation/geolocation/intro

使用此API，您可以从单元格信息（cellid，mcc，mnc和lac）中检索位置

Answer 5

如其他主题中所述，还可以查看https://labs.ericsson.com/apis/mobile-location/documentation/cell-id-look-up-api获取免费的cell-ID数据库，以获取来自cellid，mcc，mnc和lac的坐标。

谷歌地图，cellid到位置

5 个答案: