Question

我从Logcat获得以下错误堆栈跟踪：

 SqliteDatabaseCpp(1355): sqlite returned: error code = 1

 msg = table my_table has no column named check_box_status,
 db=/data/data/com.example.dbtester/databases/my_database

 Error inserting check_box_status=1 price=210 check_box_label=testlabel

 table my_table has no column named check_box_status: , while compiling:
 INSERT INTO my_table(check_box_status,price,check_box_label) VALUES (?,?,?)

我猜这与下面显示的insert（）方法的middle参数为null的事实有关，

  public void insertNewRow(int checkBoxStatus, String checkBoxLabel, int price){
          ContentValues contentValues = new ContentValues();
          contentValues.put(KEY_CHECKBOX_STATUS, checkBoxStatus);
          contentValues.put(KEY_CHECKBOX_LABEL, checkBoxLabel);
          contentValues.put(KEY_PRICE, price);
          sqLiteDatabase.insert(MYDATABASE_TABLE, null, contentValues); // <---
          }

我为sqLiteDatabase.insert（）的中间参数值设置了null，但是我得到错误和上面显示的堆栈跟踪的原因可能是此变量不应为null。

从下面显示的信息中，我应该把那个现在为空的中间参数变量放入？ sqLiteDatabase.insert（MYDATABASE_TABLE，？，contentValues）;

注意我在用于创建表的字符串中显式声明了主键，“ID INTEGER PRIMARY KEY AUTOINCREMENT”我认为这与错误有关。

数据库初始化代码：

    public static final String MYDATABASE_NAME = "my_database";
    public static final String MYDATABASE_TABLE = "my_table";
    public static final int MYDATABASE_VERSION = 1;
    public static final String KEY_CHECKBOX_STATUS = "check_box_status";
    public static final String KEY_CHECKBOX_LABEL = "check_box_label";
    public static final String KEY_PRICE = "price"; 

  //create table MY_DATABASE (ID integer primary key, Content text not null);
    private static final String SCRIPT_CREATE_DATABASE =
     "CREATE TABLE IF NOT EXISTS " + MYDATABASE_TABLE + " (" + "ID INTEGER PRIMARY KEY AUTOINCREMENT, " +  
    "KEY_CHECKBOX_STATUS INTEGER, " + "KEY_CHECKBOX_LABEL TEXT, " + " KEY_PRICE INTEGER" + ");";

    SQLiteDatabase sqLiteDatabase;
    SQLiteHelper sqLiteHelper;
    Context context;

    public Database(Context c){
          context = c;
          sqLiteHelper = new SQLiteHelper(context, MYDATABASE_NAME, null, MYDATABASE_VERSION);
         }

Answer 1

在您创建的SQL中，您将KEY_CHECKBOX_STATUS作为列名而不是值check_box_status）..这就是为什么告诉table my_table has no column named check_box_status

所以创建应该是：

private static final String SCRIPT_CREATE_DATABASE =
 "CREATE TABLE IF NOT EXISTS " + MYDATABASE_TABLE + " (" + "ID INTEGER PRIMARY KEY AUTOINCREMENT, " +  
KEY_CHECKBOX_STATUS + " INTEGER, " + KEY_CHECKBOX_LABEL +" TEXT, " +  KEY_PRICE +" INTEGER" + ");";

Answer 2

您的“创建表”语法错误，因为您在引号中传递变量名称。所以像这样改变你的创建表

  "CREATE TABLE IF NOT EXISTS " + MYDATABASE_TABLE + " (" + "ID INTEGER PRIMARY KEY AUTOINCREMENT, " +  
            KEY_CHECKBOX_STATUS+" INTEGER, " + KEY_CHECKBOX_LABEL+" TEXT, " +  KEY_PRICE +" INTEGER" + ");";

Answer 3

更改

private static final String SCRIPT_CREATE_DATABASE =
 "CREATE TABLE IF NOT EXISTS " + MYDATABASE_TABLE + " (" + "ID INTEGER PRIMARY KEY AUTOINCREMENT, " +  
KEY_CHECKBOX_STATUS + " INTEGER, " + KEY_CHECKBOX_LABEL + " TEXT, " +  KEY_PRICE + " INTEGER);";

sqLiteDatabase.insert（）和SQLite错误代码1，Android数据库

3 个答案: