如何在PHP中从Android获取值

时间:2013-04-11 10:55:26

标签: php

我正在尝试为Android实现服务器端。我在android中的Forthis使用这段代码:

    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
        // Get the deviceID
        nameValuePairs.add(new BasicNameValuePair("reg_id", val[1]));
        nameValuePairs.add(new BasicNameValuePair("App_Name",val[2]));
        nameValuePairs.add(new BasicNameValuePair("App_Version", val[3]));

现在在服务器端,我想访问这些值并将其存储在数据库中。我的PHP代码:

include('connectdb.php');

$Reg_ID=$_REQUEST['reg_id'];
$App_Name=$_REQUEST['App_Name'];
$App_Version=$_REQUEST['App_Version'];

if($_REQUEST['reg_id']!='NULL' && $_REQUEST['App_Name']!='NULL' && $_REQUEST['App_Version']!='NULL')
{   
    mysqli_query($con,"INSERT INTO  registration (Reg_ID, APP_Name,App_Version)
    VALUES ('".$_REQUEST['reg_id']."', '".$_REQUEST['App_Name']."','".$_REQUEST['App_Version']."')");

}   
else
{
}   

mysqli_close($con);

但在php中我收到了这些错误:

  

注意:未定义的索引:c:\ xampp \ htdocs \ GCM \ addReg.php中的reg_id   第5行

     

注意:未定义的索引:C:\ xampp \ htdocs \ GCM \ addReg.php中的App_Name   第6行

     

注意:未定义的索引:C:\ xampp \ htdocs \ GCM \ addReg.php中的App_Version   第7行

     

警告:mysqli_close()要求参数1为mysqli,resource   在第24行的C:\ xampp \ htdocs \ GCM \ addReg.php中给出

任何帮助

修改

public class SendMail extends AsyncTask<String, String, String> {

    private String endResult;
    HttpResponse response;


    @Override
    protected String doInBackground(String... val) {

        String url=val[0];

        //Log.i("Url", url + "");

        //  Log.d("C2DM", "Sending registration ID to my application server");

        HttpPost post = new HttpPost(url);



        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);

        nameValuePairs.add(new BasicNameValuePair("reg_id", val[1]));
        nameValuePairs.add(new BasicNameValuePair("App_Name",val[2]));
        nameValuePairs.add(new BasicNameValuePair("App_Version", val[3]));








        HttpParams httpParameters = new BasicHttpParams();
        // Set the timeout in milliseconds until a connection is established.
        int timeoutConnection = 30000;
        HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
        // Set the default socket timeout (SO_TIMEOUT) 
        // in milliseconds which is the timeout for waiting for data.
        int timeoutSocket = 30000;
        HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);

        DefaultHttpClient hc = new DefaultHttpClient(httpParameters);
        ResponseHandler<String> res = new BasicResponseHandler();





        try {
            post.addHeader("Content-Type","application/x-www-form-urlencoded");
            post.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        try {
            response = hc.execute(post);
        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        return null;
    }

    @Override
    protected void onPostExecute(String result) {
        Log.i("endResult", "" + endResult);
        super.onPostExecute(result);


        publishProgress(endResult);

    }

    @Override
    protected void onProgressUpdate(String... values) {

        super.onProgressUpdate(values);
        String result = values[0];



    }

}

2 个答案:

答案 0 :(得分:1)

include('connectdb.php');

//First, check whether the values exist and only then use them.
if(isset($_REQUEST['reg_id'], $_REQUEST['App_Name'], $_REQUEST['App_Version']))
{
  $id = mysqli_real_escape_string($con, $_REQUEST['req_id']) ;
  $name = mysqli_real_escape_string($con, $_REQUEST['App_Name']) ;
  $version = mysqli_real_escape_string($con, $_REQUEST['App_Version']) ;

  $query = "INSERT INTO registration (Reg_ID, APP_Name, App_Version)
    VALUES ('{$id}', '{$name}','{$version}') ;" ;

  $result = mysqli_query($con, $query) ;
  if ($result){
    echo "Success" ;
  } else {
    echo "Failure" ;
  }
} else {
  echo "Not sufficient data for request" ;
}

我刚刚纠正了条件的基本流程并转义了特殊字符以保护您的数据库。它应该工作。

答案 1 :(得分:0)

如果要发布数据,请尝试使用$ _POST而不是$ _REQUEST。为清楚起见 - 在第7行及以下重用指定的变量($ Reg_ID,$ App_Name,$ App_Version)而不是$ _REQUEST [...]。