Question

我有xml如下

   <?xml version="1.0" standalone="yes"?>
  <epdata dbname="psyh">
<record plink="http://search.ebscohost.com/login.aspx?direct=true&amp;db=psyh&amp;AN=2009-00375-006&amp;site=ehost-live&amp;EPSource=esi">
    <item name="SubjectKeyword">life-threatening food refusal</item> 
    <item name="SubjectKeyword">life-threatening food refusal</item> 
            <item name="SubjectKeyword">nine-year-old girls</item> 
            <item name="SubjectKeyword">Maudsley model</item> 
    <item name="SubjectKeyword">family-based treatment</item> 
            <item name="SubjectKeyword">anorexia nervosa</item> 
            <item name="SubjectKeyword">eating disorders</item>
            <subitem name="ClassDescrip">Eating Disorders</subitem>
            <subitem name="ClassDescrip">Group & Family Therapy</subitem> 
            <subitem name="SubjMajDescrip">Anorexia Nervosa</subitem>
            <subitem name="SubjMajDescrip">Eating Behavior</subitem>
    <subitem name="SubjMajDescrip">Eating Disorders</subitem>
    <subitem name="SubjMajDescrip">Family Therapy</subitem>
    <subitem name="SubjMajDescrip">Food</subitem>
    <subitem name="SubjMinorDescrip">Threat</subitem> 
    <subitem name="SubjMinorDescrip">Food Refusal</subitem>

            </record>
            </epdata>

使用xslt 1.0我想要一个如下所示的输出

“威胁生命的食物拒绝; 9岁的女孩; Maudsley模型;家庭治疗;神经性厌食症;饮食失调;小组和家庭治疗;饮食行为; 家庭治疗;餐饮;威胁;食品拒绝“

Answer 1

此XSLT 1.0转换：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="text"/>
 <xsl:strip-space elements="*"/>

 <xsl:key name="kElemByVal" match="record/*"
  use="translate(.,
                 'ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                 'abcdefghijklmnopqrstuvwxyz')"/>

 <xsl:template match=
 "record/*
   [generate-id()
   =
    generate-id(key('kElemByVal',
               translate(.,
                 'ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                 'abcdefghijklmnopqrstuvwxyz'))[1])]">
   <xsl:if test="not(position()=1)">; </xsl:if>
   <xsl:value-of select="."/>
 </xsl:template>
 <xsl:template match="text()"/>
</xsl:stylesheet>

应用于提供的XML文档（更正了一个错误）：

<epdata dbname="psyh">
    <record plink="http://search.ebscohost.com/login.aspx?direct=true&amp;db=psyh&amp;AN=2009-00375-006&amp;site=ehost-live&amp;EPSource=esi">
        <item name="SubjectKeyword">life-threatening food refusal</item>
        <item name="SubjectKeyword">life-threatening food refusal</item>
        <item name="SubjectKeyword">nine-year-old girls</item>
        <item name="SubjectKeyword">Maudsley model</item>
        <item name="SubjectKeyword">family-based treatment</item>
        <item name="SubjectKeyword">anorexia nervosa</item>
        <item name="SubjectKeyword">eating disorders</item>
        <subitem name="ClassDescrip">Eating Disorders</subitem>
        <subitem name="ClassDescrip">Group &amp; Family Therapy</subitem>
        <subitem name="SubjMajDescrip">Anorexia Nervosa</subitem>
        <subitem name="SubjMajDescrip">Eating Behavior</subitem>
        <subitem name="SubjMajDescrip">Eating Disorders</subitem>
        <subitem name="SubjMajDescrip">Family Therapy</subitem>
        <subitem name="SubjMajDescrip">Food</subitem>
        <subitem name="SubjMinorDescrip">Threat</subitem>
        <subitem name="SubjMinorDescrip">Food Refusal</subitem>
    </record>
</epdata>

会产生想要的正确结果：

危及生命的食物拒绝;九岁女孩; Maudsley模型;以家庭为基础的治疗;神经性厌食症;饮食失调;集团＆amp;家庭治疗;饮食行为;家庭治疗;餐饮;威胁;食物拒绝

如何使用分号和xslt中的空格分隔多个条目，并删除重复的术语

1 个答案: