当我尝试代码时
Actor[] act =
new Actor[]
{
new Actor
{
Name = "Jacky",
ID = "JZ01",
FilmList =
{
new Film
{
Title = "Twin Brothers",
Period = Convert.ToDateTime("01/Nov/1993")
},
new Film
{
Title = "Police Story",
Period = Convert.ToDateTime("05/Aug/1989")
}
}
},
new Actor
{
Name = "Tom Cruise",
ID = "JZ09",
FilmList =
{
new Film
{
Title = "Mission Impossible I",
Period = Convert.ToDateTime("01/Jun/1998")
},
new Film
{
Title = "Mission Impossible II",
Period = Convert.ToDateTime("05/Aug/2001")
}
}
}
};
class Actor
{
string name;
string id;
List<Film> flm=new List<Film>();
public string Name
{
get { return name; }
set { name = value; }
}
public string ID
{
get { return id; }
set { id = value; }
}
public List<Film> FilmList
{
get { return flm; }
set { flm = value; }
}
}
class Film
{
string title;
DateTime period;
public string Title
{
get { return title; }
set { title = value; }
}
public DateTime Period
{
get { return period; }
set { period = value; }
}
}
...主要() ..
var sqry = from actr in Actor select actr;
我收到了“无法找到查询模式的实现。选择未找到”。
我可以知道停止执行的原因吗?
答案 0 :(得分:1)
Actor
类未实现IEnumerable
或IQueryable
,因此您无法对其进行查询(无论如何Actor
是一种类型,而不是类型的实例)...
您的意思是from actr in act select actr
吗?
答案 1 :(得分:1)
您无法直接在Actor
课程上进行选择,因为它未实施IEnumerable
或IQueryable
。您应该查询act
数组。