我有一个带有6个基本表的数据库，我在向简单摘要正确显示总和时遇到问题。这是我的精简版设置：
table: customer_info
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custID | store | custName
1 | bayport | renee
2 | bayport | april
3 | plainfield | john
4 | bayport | tree
table: deals
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dealID | custID | dealDate | empName
1 | 1 | 2013-04-01 | shak
2 | 2 | 2013-04-01 | shak
3 | 3 | 2013-04-04 | jen
4 | 4 | 2013-04-05 | shak
table: phones
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phoneID | dealID | instore | online
1 | 1 | 1 | 0
2 | 1 | 0 | 1
3 | 2 | 1 | 0
4 | 3 | 0 | 1
5 | 3 | 1 | 0
6 | 3 | 1 | 0
7 | 4 | 0 | 1
table: accessory
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accID | dealID | acName | price
1 | 1 | lanyard | 10
2 | 2 | pen | 5
3 | 4 | acc | 2
3 | 4 | blip | 15
table: others
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otherID | dealID | otName | otPrice
1 | 2 | other | 250
2 | 2 | other2 | 100
table:payments
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paymentID | dealID | cash | credit
1 | 1 | 10 | 0
2 | 2 | 0 | 355
3 | 3 | 0 | 0
4 | 4 | 17 | 0
以下是我需要的摘要：
Date | empName | instore | online | credit | cash | total | accTotal | otherTotal | countOthers
2013-04-01 | shak | 2 | 1 | 355 | 10 | 360 | 15 | 350 | 2
2013-04-04 | jen | 2 | 1 | 0 | 0 | 0 | 0 | 0 | 0
2013-04-05 | shak | 0 | 0 | 0 | 17 | 17 | 17 | 0 | 0
店员，在线，信贷，现金，总计，accTotal，otherTotal是各自列的总金额，而countOthers是“其他人”完成的数量
这是我到目前为止所尝试的，但数量就像是遍布各地
select dealDate,empName,
Sum(phone.instore) AS 'In-store',
Sum(phone.online) As 'Online',
sum(credit) AS 'Credit',
sum(cash) AS 'Cash',
sum(cash+credit) AS 'Total',
sum(price) AS 'accTotal'
sum(otprice) AS 'otherTotal'
COUNT(otName) AS 'OthersCount'
FROM customer_info
JOIN deals
LEFT join phones
ON deals.dealID = phones.dealID
LEFT JOIN payments
ON deals.dealID = payments.dealID
LEFT JOIN accessory
ON deals.dealID = accessory.dealID
LEFT JOIN others
ON deals.dealID = others.dealID
WHERE customer_info.custID = deals.custID
GROUP BY deals.dealDate
ORDER BY dealDate DESC
任何帮助将不胜感激。结果可以是由dealDate或dealID组合，哪个更容易。非常感谢你。
答案 0 :(得分：0)
我明白了！我刚刚查询了那些乘以我总数的部分。