Question

我为之前的问题道歉，因为它们含糊不清，难以回答。我仍然是编程方面的新手，我仍然在学习这一切的来龙去脉。所以请耐心等待。现在到背景资料。我正在使用python 3.3.0。我把它加载到Eclipse IDE上，这就是我用来编写代码并测试它的方法。

现在提出问题：我正在尝试学习如何创建和使用词典。因此，我的任务是创建一个价格匹配代码，通过用户界面不仅能够通过字典搜索项目（这些是键和位置和价格，这些是与键相关的值。）到目前为止我已经创建了一个足够运行的用户界面，但没有任何错误（至少在IDE中）当我运行并输入所有提示时，空字典没有更新，因此我无法调用早期输入的字典。

我有我到目前为止编写的代码，如果有人能告诉我我是否正确地做事，我想。如果有更好的方法可以解决这个问题。我还在学习，所以围绕代码术语的更详细解释会很有用。

print("let's Price match") 
decition = input("Are you adding to the price match list?") 
if decition == "yes": 
    pricematchlist = {"Snapple":["Tops",99]} 
    location = input("Now tell me where you shopped") 
    item = input("Now what  was the item") 
    price = input("Now how much was the item") 
    int(price) 
    pricematchlist[item]=location,price 
    print(pricematchlist) 
else:  
    pricematchlist = {"Snapple":["Tops",99]}  
    reply = input("Ok so you want to search up a previous price?") 
    if reply == "yes": 
        search = input("What was the item?")
        pricematchlist.item(search)

Answer 1

这些是一些小的改动。对于词典：您正确使用它们。

print("let's Price match") 
pricemathlist = {"Snapple":["Tops", 99]} # assign it here
decition = input("Are you adding to the price match list?").lower() #"Yes"-->"yes"
if decition == "yes": 
    # pricematchlist = {"Snapple":["Tops",99]}
    # If this whole code block is called repeatedly, you don't want to reassign it
    location = input("Now tell me where you shopped") 
    item = input("Now what  was the item") 
    price = int(input("Now how much was the item"))
    # int(price) does nothing with reassigning price
    pricematchlist[item]=location,price 
    print(pricematchlist) 
else:    
    reply = input("Ok so you want to search up a previous price?").lower()
    if reply == "yes": 
        search = input("What was the item?")
        print pricematchlist[search] # easier way of accessing a value

使用字典，练习代码

1 个答案: