我正在尝试制作一个很酷的PHP函数来替换东西,但我得到解析错误的原因并不明显。我错过了什么吗?
error_reporting(E_ALL);
$array_pairs = array( '{{simple}}' => 'simple_value', '{{organization}}' => 'Apple Inc');
function the_replace($aray_pairs, $content){
foreach($aray_pairs as $a => $b)
{
$content = str_replace($a, $b, $content);
return $content;
}
$invoice = '{{organization}} is a {{simple}}';
$invoice = replace_values($array_pairs, $invoice);
echo $invoice;
答案 0 :(得分:1)
失踪} 功能名称也不匹配
error_reporting(E_ALL);
$array_pairs = array( '{{simple}}' => 'simple_value', '{{organization}}' => 'Apple Inc');
function replace_values($aray_pairs, $content){ // function names didn't match too.
foreach($aray_pairs as $a => $b)
{
$content = str_replace($a, $b, $content);
}
return $content;
} // here
$invoice = '{{organization}} is a {{simple}}';
$invoice = replace_values($array_pairs, $invoice);
echo $invoice;