我可以根据线条模式将文本文件与Regex分组

Question

给定一个文件：

Timestamp: some text and a number 1
Timestamp: some text and a number 33
Timestamp: some text and a number 1
Timestamp: some text and a number 22
Something totally different, maybe a new pattern
Timestamp: some text and a number 4
Timestamp: some text and a number 2
Something totally different, maybe a new pattern
Something totally different, maybe a new pattern

我想获得第1行到第4行（TYPE1）和第5行（TYPE2），第6,7行（TYPE1）和第8,9行（TYPE2）的分组。

这可以在一个regualar表达式中完成，还是应该为每种类型创建一个表达式，然后逐行检查，如果前一行是相同的类型？

最后我需要返回一个分组列表（int start_char，int end_char）

Answer 1

你可以试试这个

string[] lines = System.IO.File.ReadAllLines("your taext file");

       var Groups =( 
                from w in lines 
                group w by w[0] into g 
                select new { FirstLetterLine = g.Key, Lins = g });