我有2个输入文件,input.txt
和datainput.txt
。我检查input.txt
的第2列是否与datainput.txt
的第1列匹配,如果它们匹配,则我将orthodb_id
放在输出文件的末尾相关行。
input.txt中:
5 21 218
6 11 1931
7 26 173
datainput.txt:
>21|95|28|5
Computer
>11|28|5|5
Cate
code.py:
import csv
with open('input.txt', 'rb') as file1:
file1_data = dict(line.split(None, 2)[1::-1] for line in file1 if line.strip())
with open('data.txt', 'rb') as file2, open('output.txt', 'wb') as outputfile:
output = csv.writer(outputfile, delimiter='|')
for line in file2:
if line[:1] == '>':
row = line.strip().split('|')
key = row[0][1:]
if key in file1_data:
output.writerow(row + [file1_data[key]])
这是我用我的代码获得的输出:
>21|95|28|5|5
>11|28|5|5|6
答案 0 :(得分:1)
您只需在代码中添加else
块即可获得所需的输出:
import csv
with open('input.txt', 'rb') as file1:
file1_data = dict(line.split(None, 2)[1::-1] for line in file1 if line.strip())
with open('data.txt', 'rb') as file2, open('output.txt', 'wb') as outputfile:
output = csv.writer(outputfile, delimiter='|')
for line in file2:
if line[:1] == '>':
row = line.strip().split('|')
key = row[0][1:]
if key in file1_data:
output.writerow(row + [file1_data[key]])
else:
outputfile.write(line)