Question

我一直在尝试使用asp FileUpload控件执行图像的简单上传操作，并将其保存在Oracle数据库中。虽然我已经硬编了几行，但我还是成功了。但是，我真的想了解这个问题，并寻求专家意见。经过大量的谷歌搜索后，我尝试在我的网络应用程序中使用各种代码片段，最终失败了。以下代码部分适用于我。

protected void btnSubmit_Click(object sender, EventArgs e)
    {
        String strFileName = Path.GetFileName(imgUpload.PostedFile.FileName);
        String strFileExtension = Path.GetExtension(imgUpload.PostedFile.FileName);
        byte[] byteArray = null;
        if (imgUpload.PostedFile != null)
        {
            using (FileStream fs = new FileStream(strFileName, FileMode.Open, FileAccess.Read, FileShare.Read))
            {
                byteArray = new byte[fs.Length];
                int iBytesRead = fs.Read(byteArray, 0, (int)fs.Length);
            }
            string sql = " INSERT INTO IMAGETBL(ID,IMAGE) VALUES(:ID, :IMAGE) ";
            OracleConnection conn = new OracleConnection("Data Source=(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=localhost)(PORT=1521)))(CONNECT_DATA=(SERVER=DEDICATED)(SERVER_NAME=XE)));User Id=sakthi_studdb;Password=sakthi;");
            try
            {
                conn.Open();
                OracleCommand cmd = new OracleCommand(sql, conn);
                cmd.Parameters.Add("ID", OracleDbType.Int32, 4, ParameterDirection.Input);
                cmd.Parameters.Add("IMAGE", OracleDbType.Blob, byteArray, ParameterDirection.Input);
                cmd.ExecuteNonQuery();
                secondlabel.Text = "Image added to blob field";
            }
            catch (Exception ex)
            {
                secondlabel.Text = ex.ToString();
            }
            finally
            {
                conn.Close();
            }
        }

    }

当我运行此代码时，它会提示Filenotfound错误。找不到文件'C：\ Program Files \ Common Files \ Microsoft Shared \ DevServer \ 10.0' 然后为了使它工作，我不得不手动复制粘贴我的图像文件在上述位置。必须有一种方法来创建目录并暂时保存图像。稍后应在Oracle数据库中插入相同的图像。

                    HttpPostedFile imgFile = imgUpload.PostedFile;
            int imgFileLength = imgFile.ContentLength;
            if (imgFileLength > 0)
            {
                var fileName = System.IO.Path.GetFileName(imgFile.FileName);
                var fileUpload = Path.Combine(Server.MapPath("~/user_uploads"), fileName);
                imgFile.SaveAs(fileUpload);
                if (System.IO.File.Exists(fileUpload))
                {
                    using (System.IO.StreamReader sr = new System.IO.StreamReader(fileUpload))
                    {
                        var input = sr.ReadToEnd();
                        var lines = Regex.Split(input, "#!#");

另一个......

string path = HttpContext.Current.ApplicationInstance.Server.MapPath("~/user_uploads"); string fn = System.IO.Path.GetFileName(imgUpload.PostedFile.FileName); imgUpload.PostedFile.SaveAs(System.IO.Path.Combine(path, fn)); Mylabel.Text = Path.GetFullPath(strFileName); imgUpload.PostedFile.SaveAs(strFileName);

我几乎不理解这些片段。此外，如果你知道更简单的方法来完成相同的建议。请帮助我！

Answer 1

如果您只是上传文件并希望将其推送到Db，那么您应该只需抓取postedFile值并使用它即可。

调整你的第一个剪辑：

protected void btnSubmit_Click(object sender, EventArgs e)
{
    if (imgUpload.PostedFile != null)
    {
        BinaryReader b = new BinaryReader(imgUpload.InputStream);
        byte[] byteArray = b.ReadBytes(imgUpload.ContentLength);

        string sql = " INSERT INTO IMAGETBL(ID,IMAGE) VALUES(:ID, :IMAGE) ";
        OracleConnection conn = new OracleConnection("Data Source=(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=localhost)(PORT=1521)))(CONNECT_DATA=(SERVER=DEDICATED)(SERVER_NAME=XE)));User Id=sakthi_studdb;Password=sakthi;");
        try
        {
            conn.Open();
            OracleCommand cmd = new OracleCommand(sql, conn);
            cmd.Parameters.Add("ID", OracleDbType.Int32, 4, ParameterDirection.Input);
            cmd.Parameters.Add("IMAGE", OracleDbType.Blob, byteArray, ParameterDirection.Input);
            cmd.ExecuteNonQuery();
            secondlabel.Text = "Image added to blob field";
        }
        catch (Exception ex)
        {
            secondlabel.Text = ex.ToString();
        }
        finally
        {
            conn.Close();
        }
    }

}

上传图像（blob类型）-Asp.Net-C＃-Oracle 11g xe

1 个答案: