Question

我需要反转存储在double [] img中的给定长度和宽度的图像; 这是我第一次使用数组。指令是嵌套for循环，y（行）上的外循环和x（列）上的内循环，并反转每个horizantal数组。这就是我所拥有的，它不起作用。

width = ImageLibrary.getImageWidth();
height = ImageLibrary.getImageHeight();

  for(i = 0; i < width ; i++){
    for(j = 0; j < height ; j++){
       for(int k = 0; k < img.length/2; k++){
           double temp = img[k];
           img[i] = img[img.length - k - 1];
           img[img.length - k - 1] = temp;
}
    }
  }

我真的不确定该怎么办？当它说要反转水平阵列时，我这样做是否正确？谢谢

Answer 1

我认为你所寻找的更像是

width = ImageLibrary.getImageWidth();
height = ImageLibrary.getImageHeight();

// Loop from the top of the image to the bottom
for (y = 0; y < height ; y++) {

    // Loop halfway across each row because going all the way will result
    // in all the numbers being put back where they were to start with
    for (x = 0; x < width / 2 ; x++) {

        // Here, `y * width` gets the row, and `+ x` gets position in that row
        double temp = img[y * width + x];

        // Here, `width - x - 1` gets x positions in from the end of the row
        // Subtracting 1 because of 0-based index
        img[y * width + x] = img[y * width + (width - x - 1)];
        img[y * width + (width - x - 1)] = temp;
    }
}

这将镜像图像所以现在左侧是右侧，右侧是左侧

试图用Java反转存储在数组中的图像

1 个答案: