Question

我无法访问我的示例restful服务。请告诉我哪里可能有问题。

以下是代码段：

的pom.xml：

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>

<groupId>com.sample</groupId>
<artifactId>RestFulService</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>war</packaging>

<name>RestFulService</name>
<url>http://maven.apache.org</url>

<dependencies>
    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>servlet-api</artifactId>
        <version>2.4</version>
        <scope>provided</scope>
    </dependency>
    <dependency>
        <groupId>javax.servlet.jsp</groupId>
        <artifactId>jsp-api</artifactId>
        <version>2.1</version>
        <scope>provided</scope>
    </dependency>
    <dependency>
        <groupId>com.sun.jersey</groupId>
        <artifactId>jersey-server</artifactId>
        <version>1.17.1</version>
    </dependency>
    <dependency>
        <groupId>com.sun.jersey</groupId>
        <artifactId>jersey-servlet</artifactId>
        <version>1.17.1</version>
    </dependency>
    <dependency>
        <groupId>com.sun.jersey</groupId>
        <artifactId>jersey-bundle</artifactId>
        <version>1.17.1</version>
    </dependency>
</dependencies>

<build>
    <plugins>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-compiler-plugin</artifactId>
            <version>2.0.2</version>
        </plugin>
    </plugins>
</build>

WEB.XML

    <servlet>
    <servlet-name>RestfulContainer</servlet-name>
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>com.sample</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>RestfulContainer</servlet-name>
    <url-pattern>/resources/*</url-pattern>
</servlet-mapping>

如果我尝试使用以下网址访问我的示例服务，我最终会收到404错误。

RestFulService - ＆gt;是生成的war文件，我可以在tomcate管理器页面中看到该应用程序。

的http：//＆LT;＆GT;：8080 / RestFulService /资源/ sayHello的

谢谢， Girish K

Answer 1

提供的范围仅在编译和测试类路径上可用，并且不可传递。

尝试使用这些依赖项

 <dependency>
        <groupId>com.sun.jersey</groupId>
        <artifactId>jersey-server</artifactId>
        <version>1.17</version>
    </dependency>
    <dependency>
        <groupId>com.sun.jersey</groupId>
        <artifactId>jersey-servlet</artifactId>
        <version>1.17</version>
    </dependency>
    <dependency>
        <groupId>javax.ws.rs</groupId>
        <artifactId>jsr311-api</artifactId>
        <version>1.1.1</version>
    </dependency>
    <dependency>
        <groupId>com.sun.jersey</groupId>
        <artifactId>jersey-client</artifactId>
        <version>1.17</version>
    </dependency>
    <dependency>
        <groupId>com.sun.jersey</groupId>
        <artifactId>jersey-json</artifactId>
        <version>1.17</version>
    </dependency>
    <dependency>
        <groupId>org.codehaus.jettison</groupId>
        <artifactId>jettison</artifactId>
        <version>1.3.2</version>
    </dependency>
    <dependency>
        <groupId>org.codehaus.jackson</groupId>
        <artifactId>jackson-jaxrs</artifactId>
        <version>1.9.12</version>
    </dependency>

使用Maven + Eclipse + Tomcat开发泽西式restful Web服务。 404问题

1 个答案: