Table 1:Domain Link Result
======================================================================
||Column1(words) ||Column2(links) ||Column3(frequency) ||
======================================================================
1 1 Any Number
2 1 Any Number
3 1 Any Number
4 1 Any Number
1 2 Any Number
2 2 Any Number
3 2 Any Number
4 2 Any Number
Table 2:Sub Link Result
======================================================================
||Column1(words) ||Column2(sublinks) ||Column3(frequency) ||
======================================================================
1 a Any Number
2 b Any Number
3 c Any Number
4 d Any Number
1 e Any Number
2 f Any Number
3 g Any Number
4 h Any Number
And so on.
在上面的场景中,用户输入了4个单词和2个域名链接。现在,4个关键字的频率在域链接和子链接上计算,并存储在单独的表中,如上所示。我想要一个如下的汇总结果:
Table 3:Final Result
==================================================================================
||Column1(words) ||Column2(Domain links) ||Column3(Total frequency) ||
==================================================================================
Row1: 1 1 Total of frequency in both tables
2 for word "1"
----------------------------------------------------------------------------------
Row2: 2 1 Total of frequency in both tables
2 for word "2"
----------------------------------------------------------------------------------
Row3: 3 1 Total of frequency in both tables
2 for word "3"
----------------------------------------------------------------------------------
Row4: 4 1 Total of frequency in both tables
2 for word "4"
----------------------------------------------------------------------------------
我在MySQL中尝试了以下查询:
SELECT t.`keyword`, t.`link` SUM( t.`frequency` ) AS total
FROM (
SELECT `frequency`
FROM `domain_link_result`
WHERE `keyword` = 'national'
UNION ALL
SELECT `frequency`
FROM `sub_link_result`
WHERE `keyword` = 'national'
)t GROUP BY `keyword`
但是在最终结果的第2列中,我只得到第一个链接而不是第1行的两个链接。如何在一行中获得用户输入的链接或任意数量的链接?
单词和链接的VARCHAR
类型和频率为INT
类型。
答案 0 :(得分:1)
如果您要将多个行折叠为一个仍然能够查看信息,则必须使用GROUP_CONCAT
http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat
这将输出以逗号分隔的折叠值,即:一个字符串。在您的编程语言中,如果需要单独的值,可以拆分此字符串。
您的查询看起来会像这样
SELECT keyword, GROUP_CONCAT(links), SUM(frequency)
FROM (subquery)
GROUP BY keyword
哪个会输出这样的东西:
==================================================================================
||Column1(words) ||Column2(Domain links) ||Column3(Total frequency) ||
==================================================================================
Row1: 1 1,2 sum of freq.
----------------------------------------------------------------------------------
Row2: 2 1,2 sum of freq.
----------------------------------------------------------------------------------
Row3: 3 1,2 sum of freq.
----------------------------------------------------------------------------------
Row4: 4 1,2 sum of freq.
编辑:您的查询的额外帮助
您的查询对我来说有点混乱。尝试使用JOIN方法:
SELECT domain_link_results.word AS word,
GROUP_CONCAT(domain_link_results.links) AS domain_links,
domain_link_results.frequency + sub_link_results.frequency AS total_frequency
FROM domain_link_results
INNER JOIN sub_link_results
ON domain_link_results.word = sub_link_results.word
WHERE domain_link_results.word = "national"
GROUP BY domain_link_results.word
另一方面,最好在同一个表中包含所有链接,并使用额外的字段来确定它是域链接还是子链接。在不了解您的系统的情况下,很难说。