Question

我正在使用以下标题将对象序列化为XML。

<agr:ABWInvoice 
    xmlns:agr="http://services.agresso.com/schema/ABWInvoice/2011/11/14"
    xsi:schemaLocation="http://services.agresso.com/schema/ABWInvoice/2011/11/14 http://services.agresso.com/schema/ABWInvoice/2011/11/14/ABWInvoice.xsd" 
    xmlns:agrlib="http://services.agresso.com/schema/ABWSchemaLib/2011/11/14" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 >

但是，我想要类似下面的内容：（唯一的区别在于没有命名空间的第一个xmlns）

<agr:ABWInvoice 
   xmlns="http://services.agresso.com/schema/ABWInvoice/2011/11/14"
   xsi:schemaLocation="http://services.agresso.com/schema/ABWInvoice/2011/11/14 http://services.agresso.com/schema/ABWInvoice/2011/11/14/ABWInvoice.xsd" 
   xmlns:agrlib="http://services.agresso.com/schema/ABWSchemaLib/2011/11/14" 
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  >

我使用以下代码：

XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("xsi", "http://www.w3.org/2001/XMLSchema-instance");
ns.Add("agrlib", "http://services.agresso.com/schema/ABWSchemaLib/2006/11/20");
ns.Add("agr", "http://services.agresso.com/schema/ABWInvoice/2006/11/20");

XmlSerializer serializer = new XmlSerializer(typeof(ABWInvoice2006));
TextWriter textWriter = new StreamWriter(xmlFile);
serializer.Serialize(textWriter, abwInvoice, ns);
textWriter.Close();

我也试过了，但没有给出所需的输出：

XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("xsi", "http://www.w3.org/2001/XMLSchema-instance");
ns.Add("agrlib", "http://services.agresso.com/schema/ABWSchemaLib/2006/11/20");
ns.Add("", "http://services.agresso.com/schema/ABWInvoice/2006/11/20");

更新：

@Vladimir Frolov带领我使用以下方法解决问题：

[Serializable]
[XmlRootAttribute(Namespace = "http://services.agresso.com/schema/ABWInvoice/2006/11/20", IsNullable = true)]
public class ABWInvoice2006
{
...
}

Answer 1

尝试在XmlSerializer构造函数中指定XmlRootAttribute。这是一个example。

XML空白名称空间

更新：

1 个答案: