Question

我知道这是一个非常奇怪的问题，但是说我有这种类型的字符串

local string_1 = "{ [name] = "string_1", [color] = "red" }"
local string_2 = "{ [name] = "string_2", [color] = "blue" }"
local string_3 = "{ [name] = "string_3", [color] = "green" }"

我可以使用table.insert或其他东西将它们变成这个

local table_1 = {
    { [name] = "string_1", [color] = "red" };
    { [name] = "string_2", [color] = "blue" };
    { [name] = "string_3", [color] = "green" };
}

Answer 1

这些字符串似乎是Lua代码。假设这些字符串的格式是固定的，即您不能选择JSON或其他表示，那么正确的做法可能就是将它们作为Lua代码加载并执行它们。您可能希望对代码进行沙箱化，具体取决于这些字符串的来源。

这样做的方法因Lua 5.1和Lua 5.2而异。你使用的是哪个版本？

这是在Lua 5.1中执行此操作的示例。我假设您的示例输入实际上不是您想要的，并且name和color意味着是字符串键，而不是对变量的引用。如果它们是变量，则需要对环境进行破坏。

local strings = {
    "{ name = \"string_1\", color = \"red\" }",
    "{ name = \"string_1\", color = \"red\" }",
    "{ name = \"string_3\", color = \"green\" }"
}

-- parses a string that represents a Lua table and returns the table
local function parseString(str)
    local chunk = loadstring("return " .. str)
    -- Sandbox the function. Does it need any environment at all?
    -- Sample input doesn't need an environment. Let's make it {} for now.
    setfenv(chunk, {})
    return chunk()
end

local tables = {}
for _, str in ipairs(strings) do
    table.insert(tables, parseString(str))
end

Answer 2

在我看来，您需要解析一些JSON字符串。这可以通过LuaJSON或other ...

来完成

Answer 3

这适用于Lua 5.1＆amp; 5.2

local string_1 = '{ [name] = "string_1", [color] = "red" }'
local string_2 = '{ [name] = "string_2", [color] = "blue" }'
local string_3 = '{ [name] = "string_3", [color] = "green" }'

local function str2tbl(str)
   return assert((loadstring or load)('return '..str:gsub('%[(.-)]','["%1"]')))()
end

local table_1 = {}
table.insert(table_1, str2tbl(string_1))
table.insert(table_1, str2tbl(string_2))
table.insert(table_1, str2tbl(string_3))

字符串到表

3 个答案: