我有一个小问题,我确信有人有解决方案 我有一组从无符号整数转换的二进制数据
$ _ BIN = pack('I *',3563547,6587568,5468456,6458568,4568568);
我希望将其插入包含varbinary列
的表中$ strSQL =“INSERT INTO table_name(id,ba)VALUES($ id,$ _BIN)”;
由于某种原因我得到以下错误
Erreur SQL:您的SQL语法有错误;检查与MySQL服务器版本对应的手册,以便在第1行的“_”附近使用正确的语法 SQL字符串:INSERT INTO table_name(id,ba)VALUES(467,('ùZ¢O ^, |EòÇjÞ|EEÎóÇjÞ|EEÎóp>)
希望你们能帮帮我
答案 0 :(得分:0)
这对我有用:
DROP TABLE IF EXISTS `binary`;
CREATE TABLE `binary`(
id INT NOT NULL AUTO_INCREMENT,
ba VARBINARY( 100 ),
PRIMARY KEY(`id`)
) ENGINE=MYISAM;
和PHP代码(使用PDO):
<?php
$db = new PDO('mysql:dbname=test;host=localhost:4040','xxx','xxxx');
$_BIN=pack('I*', 3563547,6587568,5468456,6458568,4568568);
$rs = $db->prepare("INSERT INTO `binary`(`ba`) VALUES(?)");
$rs->execute(array($_BIN));
<强>更新强>
根据您建议的具有命名参数的代码查看下面的代码:
<?php
$_SNB = 23;
$_USR = "toto";
$_BIN = pack('I*', 24325, 2556456, 547577, 675746, 535646, 4564575, 575474, 4735);
$db = new PDO('mysql:host=localhost:4040;dbname=test','xxxx','xxxx');
$db->exec('SET CHARACTER SET utf8');
$rs = $db->prepare("INSERT INTO `spw_license` (`serial_num`, `user`, `ba_struct`)
VALUES(:serial_num, :username, :ba_struct)");
$rs->bindValue(':serial_num', $_SNB, PDO::PARAM_INT);
$rs->bindValue(':username', $_USR);
$rs->bindValue(':ba_struct', $_BIN, PDO::PARAM_LOB);
try {
if(!$rs->execute()) {
var_dump($db->errorInfo());
}
} catch(Exception $e) {
echo 'got Exception: ' . $e->getMessage() . PHP_EOL;
}
以下是启动此表后的表格:
mysql> select * from `spw_license`;
+------------+------+----------------------------------+
| serial_num | user | ba_struct |
+------------+------+----------------------------------+
| 23 | toto | ♣_ (☻' ∙ вO
^ _жE Є ⌂↕ |
+------------+------+----------------------------------+
1 row in set (0.00 sec)