Question

我正在运行一个sql查询，它使用内连接从两个表中提取id，catid，name，subof。

select shop.id, shop.catid, shop.name, shop_cat.catname, shop_cat.subof from shop inner join shop_cat on shop.catid = shop_cat.id where shop.active='1' order by shop_cat.catname, shop.name

现在这会导致我需要的一切，但我需要遍历结果并对subof值执行另一个sql查询（这是一个值，值是shop_cat的ID号）。我需要提取子值＃的catname，然后将结果/数组字段subof更新为cat的名称。

因此，如果原始查询为subof提供了值15，它将从shop.cat中选择catname，其中id ='15'我将从该查询中获取catname，然后为每个值更新subof = catname在具有子值的原始结果中。

编辑3/23/13 12:30 pm MST：使用Opeyemi编写的更多代码来解释我需要的更多内容。我不知道怎么解释它......

$q = "select shop.id, shop.catid, shop.name, shop_cat.catname, shop_cat.subof from shop inner join shop_cat on shop.catid = shop_cat.id where shop.active='1' order by shop_cat.catname, shop.name";
$r = mysql_query();
while(list($shopid, $catid, $name, $catname, $subof) = mysql_fetch_array($r)) {
    $getname = mysql_query("select catname from shop_cat where id='$subof'");
    $rowname = mysql_fetch_assoc($getname);
    //code to update array to change value of $subof to new $rowname['catname']
}

数据库查询运行，获取我的值。

然后我需要运行某种循环，它将遍历从查询中获取的每个PHP结果。此循环将获取子值（这是一个整数ID号），然后运行查询以获取该整数值的值catname。然后循环将更新当前结果并将subof值从整数更改为从循环中的DB中提取的catname。

我不需要随时更新数据库，我需要从第一个查询更新结果/数组。

Answer 1

您需要做的是将结果集存储在数组中并在数组中替换。

$q = "select shop.id, shop.catid, shop.name, shop_cat.catname, shop_cat.subof from shop inner join shop_cat on shop.catid = shop_cat.id where shop.active='1' order by shop_cat.catname, shop.name";
$r = mysql_query();
$dataset = array();
// Store result in an array
while($assoc = mysql_fetch_assoc($r)) {
  $dataset[] = $assoc;
}
// Update array
foreach($dataset as $data) {
  $getname = mysql_query("select catname from shop_cat where id='{$data['subof']}'");
  $rowname = mysql_fetch_assoc($getname);
  // replace data
  replace_dataset($data['subof'], $rowname);
}

function replace_dataset($key, $newname) {
  global $dataset;
  foreach($dataset as $k => $data) {
    if ($data['id'] == $key)
      $dataset[$k]['subof'] = $newname;
  }
}

Answer 2

您是否在PHP中询问如何执行此操作？如果您正在寻找如何在PHP中循环结果，那么就像这个

一样简单

$q = "select shop.id, shop.catid, shop.name, shop_cat.catname, shop_cat.subof from shop inner join shop_cat on shop.catid = shop_cat.id where shop.active='1' order by shop_cat.catname, shop.name";
$r = mysql_query();
while(list($shopid, $catid, $name, $catname, $subof) = mysql_fetch_array($r)) {
  // the values from the query are assigned to the variables
  // $shopid, $catid, $name, $catname, $subof in that order already
  mysql_query("update shop_cat set subof=catname where id='$subof'");
  // My interpretation of your query can be wrong though
  // But you should get the idea
}

Answer 3

您可以使用mysql_fetch_assoc（）或mysql_fetch_array（）或mysql_fetch_row（）函数来获取行，并可以将循环概念放在其上。

之后你可以使用mysql_fetch_field（）从中获取字段subof和id。

并在此之后更新数据库

您可以查看以下链接

http://www.php.net/manual/en/function.mysql-fetch-array.php

http://www.php.net/manual/en/function.mysql-fetch-assoc.php

http://www.php.net/manual/en/function.mysql-fetch-field.php

我希望你能有所了解。

循环遍历mysql_query并替换值OR 1查询来完成工作

3 个答案: