Question

我的操作栏sherlock中有一个列表。我想在用户点击该列表时获得。我不想知道用户何时点击某个项目，我已经知道（onNavigationItemSelected）。

在我的onCreate（）中：

// Set action bar
final ActionBar actionBar = getSherlockActivity().getSupportActionBar();
if (actionBar.getNavigationMode() != ActionBar.NAVIGATION_MODE_LIST) {
    actionBar.setNavigationMode(ActionBar.NAVIGATION_MODE_LIST);
}
actionBar.setDisplayShowTitleEnabled(false);
mSelectionAdapter = new SelectionAdapter(getSherlockActivity().getSupportActionBar().getThemedContext(), R.layout.sherlock_spinner_dropdown_item, kinds);
actionBar.setListNavigationCallbacks(mSelectionAdapter, this);

我想在用户点击操作栏中的列表导航时以编程方式检测。

Answer 1

如果您只是希望在单击某个操作栏项（例如列表菜单）时收到通知，则必须覆盖onMenuItemSelected，如下所示：

    @Override
public boolean onMenuItemSelected(int featureId, MenuItem item) {
int itemId = item.getItemId();
//using logcat you may see what the list item id is?
 Log.i(TAG, "clicked actionbar itemid is: " + itemId );

//here you can setup a listener for every actionbar item selected
    switch (itemId) {
//android.R.id.list might not be the one you are searching pls check it out and compare it to logcat and put the appropriate itemId here
    case android.R.id.list:
//do whatever you want to do when list item is clicked
        break;
    }

    return true;
}

get on ListNavigation单击操作栏

1 个答案: