Question

我有两张表User＆amp;文章表之间的关系是

型号：

class Article extends Eloquent {

  public static $table = 'article';

  public function User()
    {
    return $this->has_one('user', 'id');
    }

和

class User extends Eloquent {

  public static $table = 'user';

  public function Article()
    {
       return $this->belongs_to('article', 'id_user');
    }

我想直接在文章视图中从User获取名称值，但不能使用错误试图获得非对象的属性

我的控制器：

public function action_index()
    {

    $Article = Article::order_by('id')->paginate(10);

    return View::make('article.index')->with('$articles', $Article);
    }

我的观点：

@foreach ($articles->results as $Arti)
      <tr>
       <td>{{$Arti->id}}</td>
       <td>{{$Arti->tag}}</td>
       <td>{{$Arti->user->name }}</td>  <------ ERROR
       <td>{{$Arti->content}}</td>
       <td>{{$Arti->date}}</td>
       <td>

Answer 1

看看下面的内容，有些事情与你的不同......

文章belongs_to用户（不是has_one）
用户has_many文章（非belongs_to）
您的关系应以小写命名，复数为has_many（即articles或user）
您的关系主题应该是班级名称（即Article或User）
外键应为name relationship_id，即user_id
将::with()添加到您的查询eager load relationships
当您paginate时，您需要在视图中访问->results

class Article extends Eloquent {

    // 3: lowercase 'user'
    public function user()
    {
        // 1: Article belongs to User
        // 4: class name 'User'
        // 5: Foreign key on article table is user_id
        return $this->belongs_to('User');
    }

}

// models/user.php

class User extends Eloquent {

    // 3: lowercase plural 'articles'
    public function articles()
    {
        // 2: User has many Articles
        // 4: class name 'Article'
        return $this->has_many('Article');
    }

}

// controllers/articles.php

class Article_Controller extends Base_Controller {

    public $restful = true;

    public function get_index()
    {
        // 6: Eager load the user relationship, ::with('user')
        $articles = Article::with('user')->order_by('id')->paginate(10);
        return View::make('articles.index', compact('articles'));
    }

}

// views/articles/index.blade.php
// 7: access $articles->results from the paginator

@foreach ($articles->results as $article)

    <h1>{{ $article->title }}</h1>
    <p>By {{ $article->user->name }}</p>

@endforeach

{{ $articles->links() }}

从视图中获取价值

1 个答案: