我正在尝试按价格和评级对结果列表进行排序。为简单起见,我刚刚收到了2个结果:Rider's Lodge和Olina Lodge。我编写了一个函数,可以单向排序。
如何重复使用相同的功能对结果进行排序,以便点击“按价格排序”按升序排序,再按一次按降序排序,然后在两者之间切换?
<div class="tab-content">
<div id="filters">
<p>
<a href="javascript:sort_by_rating();">Sort by Rating</a>
<br>
<a href="javascript:sort_by_price();">Sort by Price</a>
</p>
</div>
<div id="div_hotel_results" class="tab-pane active">
<form id="hotel-form">
...
</form>
<div class="results-row">
<h5>Riders Lodge</h5>
<span class="label label-info price">$103.64</span>
<span class="rating" data-rating="3.0">3.0</span>
</div>
<div class="results-row">
<h5>Olina Lodge</h5>
<span class="label label-info price">$99.64</span>
<span class="rating" data-rating="2.5">2.5</span>
</div>
</div>
</div>
<script type="text/javascript">
function sort_by_price () {
var sorted_list = [];
$('.price').each(function (index) {
sorted_list[index] = $(this).parent().parent().remove();
sorted_list[index]['cleaned_price'] = parseFloat($(this).text().replace(/[^0-9\.]+/g,""));
});
sorted_list.sort(function (a, b) {
if (a['cleaned_price'] == b['cleaned_price']) {
return 0;
} else if (a['cleaned_price'] > b['cleaned_price']) {
return 1;
} else {
return -1;
}
});
$('#hotel-form').after(sorted_list);
}
</script>
答案 0 :(得分:6)
这是一个例子。我相信你只想要价格,而不是评级。我创建了一个变量,可以帮助跟踪排序的当前状态。然后根据它对上升/下降进行排序。
我还将你的事件绑定移到了html之外。
<强> HTML 强>
<div class="tab-content">
<div id="filters">
<p>
<a class="sortByRating" href="#" >Sort by Rating</a>
<br>
<a class="sortByPrice" href="#">Sort by Price</a>
</p>
</div>
<div id="div_hotel_results" class="tab-pane active">
<form id="hotel-form">
...
</form>
<div class="results">
<div class="results-row">
<h5>Riders Lodge</h5>
<span class="label label-info price">$103.64</span>
<span class="rating" data-rating="3.0">3.0</span>
</div>
<div class="results-row">
<h5>Olina Lodge</h5>
<span class="label label-info price">$99.64</span>
<span class="rating" data-rating="2.5">2.5</span>
</div>
</div>
</div>
</div>
<强>使用Javascript:强>
var ascending = false;
$('.tab-content').on('click','.sortByPrice',function(){
var sorted = $('.results-row').sort(function(a,b){
return (ascending ==
(convertToNumber($(a).find('.price').html()) <
convertToNumber($(b).find('.price').html()))) ? 1 : -1;
});
ascending = ascending ? false : true;
$('.results').html(sorted);
});
var convertToNumber = function(value){
return parseFloat(value.replace('$',''));
}
答案 1 :(得分:0)
//package algorithm.sort;
public class QuickSort
{
public static void main(String[] args) {
int[] x = { 9, 2, 4, 7, 3, 7, 10 };
printArray(x);
int low = 0;
int high = x.length - 1;
quickSort(x, low, high);
printArray(x);
}
public static void quickSort(int[] arr, int low, int high) {
if (arr == null || arr.length == 0)
return;
if (low >= high)
return;
//pick the pivot
int middle = low + (high - low) / 2;
int pivot = arr[middle];
//make left < pivot and right > pivot
int i = low, j = high;
while (i <= j) {
while (arr[i] < pivot) {
i++;
}
while (arr[j] > pivot) {
j--;
}
if (i <= j) {
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
i++;
j--;
}
}
//recursively sort two sub parts
if (low < j)
quickSort(arr, low, j);
if (high > i)
quickSort(arr, i, high);
}
public static void printArray(int[] x) {
for (int a : x)
System.out.print(a + " ");
System.out.println();
}
}