Question

我会很快。我有6个图像，附有6个手势和一个IBAction。我希望每个手势都将一个参数传递给动作，所以我不必编写6个单独的动作。这是我的代码：

    oneImage =[[UIImageView alloc]initWithImage:[UIImage imageNamed:@"one.gif"]];
    two Image=[[UIImageView alloc]initWithImage:[UIImage imageNamed:@"two.gif"]];
    +4 more images

     UITapGestureRecognizer *oneGest=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(insertChar:)];
         UITapGestureRecognizer *twoGest=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(insertChar:)];
    +4 more gestures


    -(IBAction)insertChar:(id)sender
    {

    textfield.text = [textfield.text stringByAppendingString:@" PASS HERE VALUE FROM GESTURE,"ONE","TWO",etc "];
    }

Answer 1

无法将任意数据传递给insertChar:方法。 sender将是手势识别器。这是一个可能的解决方案：

oneImage =[[UIImageView alloc]initWithImage:[UIImage imageNamed:@"one.gif"]];
oneImage.tag = 1;
twoImage=[[UIImageView alloc]initWithImage:[UIImage imageNamed:@"two.gif"]];
twoImage.tag = 2;
// +4 more images

UITapGestureRecognizer *oneGest=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(insertChar:)];
UITapGestureRecognizer *twoGest=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(insertChar:)];
// +4 more gestures

-(IBAction)insertChar:(UITapGestureRecognizer *)sender {
    static NSString *labels[6] = { @"ONE", @"TWO", ... @"SIX" };
    UIView *view = sender.view;
    NSInteger tag = view.tag;
    NSString *label = labels[tag - 1]; // since tag is 1-based.

    textfield.text = [textfield.text stringByAppendingString:label];
}

Answer 2

您需要以某种方式将-(IBAction)insertChar:(id)sender中作为参数获得的“发件人”值与您创建的UIImageView相关联。

动作方法如下所示：

-(IBAction)insertChar:(id)sender
{

 UIGestureRecognizer *gestureRecognizer = (UIGestureRecognizer*)sender;
 UIView *view = gestureRecognizer.view;
//do whatever you want with the view that has the gestureRecgonizer's event on

}

然后，您可以通过不同方式链接您的视图。一种方法是使用tag属性。

将值传递给IBAction

2 个答案: