我正在尝试获取A,MX和NS A服务器记录,如下所示:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <netinet/in.h>
#include <resolv.h>
#include <netdb.h>
#define N 4096
int main (int argc, char *argv[])
{
u_char nsbuf[N];
char dispbuf[N];
ns_msg msg;
ns_rr rr;
int i, l;
if (argc < 2) {
printf ("Usage: %s <domain>\n", argv[0]);
exit (1);
}
// HEADER
printf("Domain : %s\n", argv[1]);
// ------
// A RECORD
printf("A records : \n");
l = res_query(argv[1], ns_c_any, ns_t_a, nsbuf, sizeof(nsbuf));
if (l < 0)
{
perror(argv[1]);
}
ns_initparse(nsbuf, l, &msg);
l = ns_msg_count(msg, ns_s_an);
for (i = 0; i < l; i++)
{
ns_parserr(&msg, ns_s_an, 0, &rr);
ns_sprintrr(&msg, &rr, NULL, NULL, dispbuf, sizeof(dispbuf));
printf("\t%s \n", dispbuf);
}
//------------
// MX RECORD
printf("MX records : \n");
l = res_query(argv[1], ns_c_any, ns_t_mx, nsbuf, sizeof(nsbuf));
if (l < 0)
{
perror(argv[1]);
}
else
{
#ifdef USE_PQUERY
/* this will give lots of detailed info on the request and reply */
res_pquery(&_res, nsbuf, l, stdout);
#else
/* just grab the MX answer info */
ns_initparse(nsbuf, l, &msg);
l = ns_msg_count(msg, ns_s_an);
for (i = 0; i < l; i++)
{
ns_parserr(&msg, ns_s_an, i, &rr);
ns_sprintrr(&msg, &rr, NULL, NULL, dispbuf, sizeof(dispbuf));
printf ("\t%s\n", dispbuf);
}
#endif
}
// ---------
// NS RECORD
printf("NS records : \n");
l = res_query(argv[1], ns_c_any, ns_t_ns, nsbuf, sizeof(nsbuf));
if (l < 0)
{
perror(argv[1]);
}
ns_initparse(nsbuf, l, &msg);
l = ns_msg_count(msg, ns_s_an);
for (i = 0; i < l; i++)
{
ns_parserr(&msg, ns_s_an, 0, &rr);
ns_sprintrr(&msg, &rr, NULL, NULL, dispbuf, sizeof(dispbuf));
printf("\t%s \n", dispbuf);
}
// ---------
return 0;
}
根据请求收到很多相同的,即相同的A记录。与NS记录相同。我究竟做错了什么? 示例:
Domain : mail.ru
A records :
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
mail.ru. 22S IN A 94.100.191.207
MX records :
mail.ru. 1m57s IN MX 10 mxs.mail.ru.
NS records :
mail.ru. 1m50s IN NS ns.mail.ru.
mail.ru. 1m50s IN NS ns.mail.ru.
mail.ru. 1m50s IN NS ns.mail.ru.
mail.ru. 1m50s IN NS ns.mail.ru.
mail.ru. 1m50s IN NS ns.mail.ru.
mail.ru. 1m50s IN NS ns.mail.ru.
请帮忙。
答案 0 :(得分:5)
在此电话会议中:
ns_parserr(&msg, ns_s_an, 0, &rr);
第三个参数是您要检索的记录的索引。所以在你的情况下它应该是:
ns_parserr(&msg, ns_s_an, i, &rr);
尝试使用该次要修补程序编写代码,并按预期工作:
Domain : mail.ru
A records :
mail.ru. 5S IN A 94.100.191.248
mail.ru. 5S IN A 94.100.191.249
mail.ru. 5S IN A 94.100.191.250
mail.ru. 5S IN A 94.100.191.201
mail.ru. 5S IN A 94.100.191.202
mail.ru. 5S IN A 94.100.191.203
mail.ru. 5S IN A 94.100.191.204
mail.ru. 5S IN A 94.100.191.205
mail.ru. 5S IN A 94.100.191.206
mail.ru. 5S IN A 94.100.191.207
mail.ru. 5S IN A 94.100.191.208
mail.ru. 5S IN A 94.100.191.209
mail.ru. 5S IN A 94.100.191.210
mail.ru. 5S IN A 94.100.191.241
mail.ru. 5S IN A 94.100.191.242
mail.ru. 5S IN A 94.100.191.243
mail.ru. 5S IN A 94.100.191.244
mail.ru. 5S IN A 94.100.191.245
mail.ru. 5S IN A 94.100.191.246
mail.ru. 5S IN A 94.100.191.247
MX records :
mail.ru. 7m14s IN MX 10 mxs.mail.ru.
NS records :
mail.ru. 3m35s IN NS ns2.mail.ru.
mail.ru. 3m35s IN NS ns.mail.ru.
mail.ru. 3m35s IN NS ns4.mail.ru.
mail.ru. 3m35s IN NS ns5.mail.ru.
mail.ru. 3m35s IN NS ns1.mail.ru.
mail.ru. 3m35s IN NS ns3.mail.ru.