JSON显然看起来像这样。
{\"amount\":10,\"conversion_id\":\"5145fd4e04af9\",\"extra_params\":
{\"ip\":\"99.237.185.67\",\"user_agent\":\"Mozilla/5.0 (Windows NT 6.1; WOW64)
AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97
Safari/537.11\"},\"job_title\":\"Answer a few questions about a website (Canada -
Sunday task #1) (Canada Only)\",\"adjusted_amount\":8.0}
但是json_decode在php中不起作用。 HELP ???
答案 0 :(得分:3)
这不是有效的JSON。在JSON中,必须使用"
引用键,因此您的JSON内容将是
{
"payload": {
"conversion_id": "32402345984532934511",
"amount": 50,
"adjusted_amount": 25,
"job_title": "The title of the last job they completed (and 2 other jobs)"
},
"signature": "1221299611f823b8c30a347373b449ad"
}