我有以下查询,用于根据software_id和level过滤行。 我已将条件放在ON-Clause中,因为我仍然希望返回行,其中JobadvertsSoftware表中没有相应的行。
SELECT `Jobadvert`.`id` FROM `jobadverts` AS `Jobadvert`
LEFT JOIN `users` AS `User` ON (`Jobadvert`.`user_id` = `User`.`id`)
LEFT JOIN `jobadverts_softwares` AS `JobadvertsSoftware_0` ON
(`Jobadvert`.`id` = 'JobadvertsSoftware_0.jobadvert_id' AND
(`JobadvertsSoftware_0`.`software_id` = '32' AND
`JobadvertsSoftware_0`.`level` IN ('1', 4)))
WHERE `Jobadvert`.`active` = 1 AND `User`.`premium` = '1' AND
Jobadvert`.`department_id` = (5)
GROUP BY `Jobadvert`.`id`
问题是它还会返回JobadvertsSoftware行,其中level为例如2 同样,如果我把它放在WHERE子句中,它将过滤掉不存在JobadvertsSoftware的行,而不应该这样做。 如何告诉MySQL返回Jobadvert的所有行,其中给定的software_id和级别匹配或为NULL?
答案 0 :(得分:0)
试试这个:
SELECT `Jobadvert`.`id`, `JobadvertsSoftware_0`.`level`
FROM `jobadverts` AS `Jobadvert`
LEFT JOIN `users` AS `User` ON (`Jobadvert`.`user_id` = `User`.`id`)
INNER JOIN `jobadverts_softwares` AS `JobadvertsSoftware_0` ON
(`Jobadvert`.`id` = 'JobadvertsSoftware_0.jobadvert_id' AND
(`JobadvertsSoftware_0`.`software_id` = '32' AND
`JobadvertsSoftware_0`.`level` IN ('1', 4)))
WHERE `Jobadvert`.`active` = 1 AND `User`.`premium` = '1' AND
Jobadvert`.`department_id` = (5)
GROUP BY `Jobadvert`.`id`
Saludos!
答案 1 :(得分:0)
试试这个(有些字段在字符串上是数字有点不清楚,可能会更正):
SELECT distinct(`Jobadvert`.`id`) FROM `jobadverts` AS `Jobadvert`
LEFT JOIN `users` AS `User` ON (`Jobadvert`.`user_id` = `User`.`id`)
LEFT JOIN `jobadverts_softwares` AS `JobadvertsSoftware_0`
ON `Jobadvert`.`id` = `JobadvertsSoftware_0.jobadvert_id`
WHERE
`Jobadvert`.`active` = 1
AND `User`.`premium` = '1'
AND Jobadvert`.`department_id` = (5)
AND JobadvertsSoftware_0`.`software_id` = '32'
AND (`JobadvertsSoftware_0`.`level` IN (1, 4) OR `JobadvertsSoftware_0`.`level` is NULL)
答案 2 :(得分:0)
假设连接不需要ON子句中的级别参数,您可以在Software表上执行嵌套SELECT,以清除首先不需要的数据:
SELECT * FROM jobadverts_softwares
WHERE
(`software_id` = 32 OR `software_id` IS NULL) --Select all software_id that are 32 or null
AND
`level` IN (1, 4)
然后,您可以将其作为嵌套语句合并到主SQL查询中,这样您只需加入在LEFT JOIN中过滤的数据,但保留所需的任何空值:
SELECT `Jobadvert`.`id`
FROM `jobadverts` AS `Jobadvert`
LEFT JOIN `users` AS `User`
ON `Jobadvert`.`user_id` = `User`.`id`
LEFT JOIN
( --Software Subquery
SELECT `jobadvert_id`, `level` FROM jobadverts_softwares
WHERE
(`software_id` = 32 OR `software_id` IS NULL) --Select all software_id that are 32 or null
AND
`level` IN (1, 4)
) AS `software_subquery`
ON `Jobadvert`.`id` = `software_subquery`.`jobadvert_id`
WHERE
`Jobadvert`.`active` = 1
AND
`User`.`premium` = '1'
AND
`Jobadvert`.`department_id` = 5
ORDER BY `Jobadvert`.`id` --Changed GROUP BY to ORDER BY as not needed
这是未经测试的,但请尝试一下,看看这是否会有所帮助。
答案 3 :(得分:-1)
试试这个:
SELECT j.id
FROM jobadverts j
LEFT JOIN User u ON (j.user_id = u.id)
LEFT JOIN jobadverts_softwares AS js ON
(j.id = js.jobadvert_id)
WHERE j.active = 1
AND u.premium = '1'
AND j.department_id = (5)
AND js.software_id` = '32'
AND js.level IN ('1', 4)))
除非以某种方式对数据求和,否则您不需要GROUP BY。