所以我对Java相对较新,并尝试使用JButton创建一个棋盘游戏,用于棋盘和棋子。但是我似乎无法通过ActionListener删除JButton。任何建议将不胜感激。
public static void main(String[] args) {
checkersBeBitchin begin = new checkersBeBitchin();
}
public checkersBeBitchin(){
box.setLayout(new BorderLayout());
makeBoard();
setVisible(true);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setLocationRelativeTo(null);
setSize(600,600);
setTitle("Checkers");
}
private void makeBoard() {
JPanel board = new JPanel();
board.setLayout(new GridLayout(8,8));
for (int i=0; i<8; i++){
for (int j=0; j<8; j++) {
squares[i][j] = new JButton();
ActionListener actionListener = new Board();
squares[i][j].addActionListener(actionListener);
if((i%2 != 0 && j%2 !=0) ||(i%2==0 && j%2 == 0) ){
squares[i][j].setBackground(Color.black);
pieceTracker[i][j]=0;
//System.out.println("Black"+i+","+j); debugging
if(i<3){
int blue = 1;
Icon piece = new ImageIcon(getClass().getResource("/resources/piece.png"));
JButton button = new JButton(piece);
//squares[i][j].setRolloverIcon("image dir") to make it prettier down the road.
squares[i][j].add(button);
pieceTracker[i][j]=blue;
ActionListener Listener = new Blue();
button.addActionListener(Listener);
}
else if (i>4){
int red=-1;
Icon piece = new ImageIcon(getClass().getResource("/resources/piece2.png"));
JButton button = new JButton(piece);
squares[i][j].add(button);
pieceTracker[i][j]=red;
ActionListener Listener = new Red();
button.addActionListener(Listener);
//squares[i][j].setRolloverSelectedIcon("/resources/piece2alt.png");
}
}
else{
squares[i][j].setBackground(Color.white);
pieceTracker[i][j]=0;
//System.out.println("White"+i+","+j); //debugging
}
board.add(squares[i][j]);
}
}
box.add(board, BorderLayout.CENTER);
}
private class Blue implements ActionListener{
public void actionPerformed (ActionEvent e){
System.out.println("You sexy Blue beast.");
Object x = e.getSource();
System.err.println(x);
squares.remove(x);
答案 0 :(得分:2)
squares.remove?它应该读取squares.remove(x)?我们能看到正方形的定义吗?它是一个阵列吗?您必须从BOARD中删除按钮而不是正方形,例如board.remove(x)