设置:
create table product_stock(product_id integer, qty integer, branch_id integer);
create table product(product_id integer, product_name varchar(255));
insert into product(product_id, product_name)
values(1, 'Apsana White DX Pencil');
insert into product(product_id, product_name)
values(2, 'Diamond Glass Marking Pencil');
insert into product(product_id, product_name)
values(3, 'Apsana Black Pencil');
insert into product_stock(product_id, qty, branch_id)
values(1, 100, 1);
insert into product_stock(product_id, qty, branch_id)
values(1, 50, 2);
insert into product_stock(product_id, qty, branch_id)
values(2, 80, 1);
我的疑问:
SELECT IFNULL(SUM(s.qty),0) AS stock,
product_name
FROM product_stock s
RIGHT JOIN product p ON s.product_id=p.product_id
WHERE branch_id=1
GROUP BY product_name
ORDER BY product_name;
返回:
+-------+-------------------------------+
| stock | product_name |
+-------+-------------------------------+
| 100 | Apsana White DX Pencil |
| 80 | Diamond Glass Marking Pencil |
+-------+-------------------------------+
1 row in set (0.00 sec)
但我希望得到以下结果:
+-------+------------------------------+
| stock | product_name |
+-------+------------------------------+
| 0 | Apsana Black Pencil |
| 100 | Apsana White DX Pencil |
| 80 | Diamond Glass Marking Pencil |
+-------+------------------------------+
要获得此结果,我应该运行什么mysql查询?
答案 0 :(得分:5)
尝试:
SELECT IFNULL(SUM(s.qty),0) AS stock,
product_name
FROM product_stock s
RIGHT JOIN product p ON s.product_id=p.product_id AND branch_id=1
GROUP BY product_name
ORDER BY product_name;
您当前的查询是在WHERE子句中过滤掉没有匹配的product_stock的产品,从而有效地将外部联接转回内部联接。