Question

我知道有很多问题和答案，但遗憾的是我认为我的情况可能是独一无二的？出于某种原因，时间变化似乎使得这一天的计算时间比计算的时间少一天。

这是我正在使用的PHP，它工作得很好，直到它开始重叠开始和结束日期之前的日光节约和夏令时之后（FYI，这是最近的问题，因为白天节约时间从本周末开始！）：

//$lastDate and $firstDate are 2 unix timestamps with valid month, day, and year values.
//The times are irrelevant at this point, they are only meant to represent a day.

//I start by making sure these have the same time values.
$lastDate = mktime(23, 59, 59, date("m", $lastDate), date("j", $lastDate), date("Y", $lastDate));
$firstDate = mktime(23, 59, 59, date("m", $firstDate), date("j", $firstDate), date("Y", $firstDate));

//Then calculate the total number of days in between.
$totalDays = abs(floor(($firstDate - $lastDate)/(60*60*24)));

再说一次，要明确的是，如果我没有重叠夏令时的变化，上述工作就会起作用......

供参考：

How to find the dates between two specified date?

Actual days between two unix timestamps in PHP

Finding days between 2 unix timestamps in php

而且，我现在仍然使用PHP 5.2。

修改/更新：
我在这个链接上找到了以下内容：

How to find the dates between two specified date?

和

How to calculate the the interval between 2 unix timestamps in php WITHOUT dividing by 86400 (60*60*24)

//$lastDate and $firstDate are 2 unix timestamps with valid month, day, and year values.
//The times are irrelevant at this point, they are only meant to represent a day.

//I start by making sure these have the same time values.
$lastDate = mktime(10, 00, 00, date("m", $lastDate), date("j", $lastDate), date("Y", $lastDate));
$firstDate = mktime(10, 00, 00, date("m", $firstDate), date("j", $firstDate), date("Y", $firstDate));

//Then calculate the total number of days in between. 
$totalDays = floor($firstDate / 86400) - floor($lastDate/ 86400);

现在它似乎可以用于DST的交叉。有人看到任何问题吗？

Answer 1

你是在运行PHP 5.3+吗？ DateInterval很好地解决了这个问题 http://www.php.net/manual/en/datetime.diff.php

<?php
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');

查找两个unix时间戳之间的天数的问题

1 个答案: