Question

这是一个tic tac toe发电机。仅限计算机与计算机，与通常的播放器与计算机略有不同。我为此编写了大部分代码，但我遇到的问题有时是在我生成游戏时，整个电路板都会填满，并且会出现一行X和一行O并且会出现一个关系。有时会生成两行X或两行O，并且游戏不会在第一行连续3行后停止......任何见解？谢谢。

namespace TicTacToe
{
    public partial class Form1 : Form
    {
        private Random rn = new Random();

        const int SIZE = 9;
        char[] cell = new char[SIZE];
        char firstPlayer = ' ', secondPlayer = ' ';

        private void button1_Click(object sender, EventArgs e)
        {
            //Clear the labels and starting values

            for (int i = 0; i < SIZE; i++)
            {
                cell[i] = ' ';
            }
            label10.Text = "";

            //Pick X or O to go first
            switch (rn.Next(2))
            {
                case 0: firstPlayer = 'O'; secondPlayer = 'X'; break;
                case 1: firstPlayer = 'X'; secondPlayer = 'O'; break;
            }

            //Get five non-repeating numbers from 0 to 8
            int[] positions = new int[5];
            positions[0] = rn.Next(9);
            for (int i = 1; i < 5; i++)
            {
                int temp = rn.Next(9);
                for (int j = 0; j < i; j++)
                {
                    if (temp == positions[j])
                    {
                        i--;
                        break;
                    }
                    else
                    {
                        positions[i] = temp;
                    }
                }
            }

            //Set each position found to have first players letter
            for (int i = 0; i < 5; i++)
            {
                cell[positions[i]] = firstPlayer;
            }

            for (int i = 0; i < SIZE; i++)
            {
                if (cell[i] != firstPlayer)
                {
                    cell[i] = secondPlayer;
                }
            }
            //Place cell values into the labels
            label1.Text = cell[0].ToString();
            label2.Text = cell[1].ToString();
            label3.Text = cell[2].ToString();
            label4.Text = cell[3].ToString();
            label5.Text = cell[4].ToString();
            label6.Text = cell[5].ToString();
            label7.Text = cell[6].ToString();
            label8.Text = cell[7].ToString();
            label9.Text = cell[8].ToString();

            //Check for a winner
            switch(checkWinner())
            {
                case 'T' : label10.Text = "It's a tie!"; break;
                case 'O' : label10.Text = "O Wins!"; break;
                case 'X' : label10.Text = "X Wins!"; break;
                default: label10.Text = "This will never appear"; break;
            }
        }

        private char checkWinner()
        {
            //return either 'T' for tie, 'O' for O wins, and 'X' for X wins
            char winner = ' ';
            int winning_line = 0;
            //check for a row win
            if(cell[0].Equals(cell[1]) && cell[0].Equals(cell[2]))
            {
                winning_line++;
                winner = cell[0];
            }
            if (cell[3].Equals(cell[4]) && cell[3].Equals(cell[5]))
            {
                winning_line++;
                winner = cell[3];
            }
            if (cell[6].Equals(cell[7]) && cell[6].Equals(cell[8]))
            {
                winning_line++;
                winner = cell[6];
            }

            //check for column wins
            if (cell[0].Equals(cell[3]) && cell[0].Equals(cell[6]))
            {
                winning_line++;
                winner = cell[0];
            }
            if (cell[1].Equals(cell[4]) && cell[1].Equals(cell[7]))
            {
                winning_line++;
                winner = cell[1];
            }
            if (cell[2].Equals(cell[5]) && cell[2].Equals(cell[8]))
            {
                winning_line++;
                winner = cell[2];
            }
            //check for diagonal winner
            if (cell[0].Equals(cell[4]) && cell[0].Equals(cell[8]))
            {
                winning_line++;
                winner = cell[0];
            }
            if (cell[2].Equals(cell[4]) && cell[2].Equals(cell[8]))
            {
                winning_line++;
                winner = cell[2];
            }

            if (winning_line == 0 || winning_line > 1)
            winner = 'T';

            return winner;
        }

        public int i { get; set; }
    }
}

Answer 1

if (winning_line == 0 || winning_line > 1)

如果有两条线路，它将会拉开一条平局。如果你想在一条线路上停下来，你需要在每次搬家后检查一个胜利者，而不是在整个董事会被填满之后。

Answer 2

第二个对角线获胜者检查应该是6而不是8。

您目前正在检查：
X O O
O X O
O O X

和：
O O X
O X O
O O X

显然最后的x应该在左边。

正如其他人发布的那样。制作两行不应该导致平局。一个玩家甚至可以单独制作两条线，造成平局更改函数以在找到获胜行时立即返回结果，并在每次移动后检查它。

Answer 3

这有效：你需要摆脱......

if（winning_line == 0 || winner_line＆gt; 1）

用这三段代码替换那行代码：

    if (winnerX == " X ")
    {
        theWinner = winnerX;
    }
    if (winnerO == " O ")
    {
        theWinner = winnerO;
    }
    if(winnerX == " X " && winnerO == " O ")
    {
        winnerT = " T ";
        theWinner = winnerT;
    }

所以我所做的就是改变一些事情。我没有使用“winner_line ++;”一点代码。相反，我为每个if语句检查做了类似的事情。

    if (cell[2, 0].Equals(cell[1, 1]) && cell[2, 0].Equals(cell[0, 2]))
        {
            if (cell[2, 0] == 0)
            {
                winnerX = " X ";
            }

            else if (cell[2, 0] == 1)
            {
                winnerO = " O ";
            }
        }

所以我有4个字符串，我正在使用，一个跟踪如果X有一个获胜线，同样是O.然后我有winT字符串用于跟踪领带。它仅用于代替你的旧领带检查if语句的位置。

如果您决定使用字符串而不是整数，那么您还需要更改switch语句，即

    switch (checkWinner())
        {
            case " X ": 
                textBox1.Text = "X Wins!";
                break;
            case " O ":
                textBox1.Text = "O Wins!";
                break;
            case " T ": 
                textBox1.Text = "It's a tie!";
                break;
        }

Answer 4

你认为你应该有一个给出一个网格的功能，一个新的棋子告诉你游戏是否结束了。然后，如果游戏结束，你知道胜利者是最后一个玩家。

我认为Marthyi的开源项目MikMak有一个完美的实现，见

bool IsFinished(Grid currentState, Pawn newPawn)

在：

https://github.com/Marthyi/MikMak/blob/master/MikMakSolution/Morpion/MorpionManager.cs

祝你好运！

Tic Tac Toe - 检测胜利，失败或平局

4 个答案: