如何避免C ++ 11中<thread>抛出的异常?</thread>

时间:2013-03-07 09:13:49

标签: c++ multithreading c++11

我正在尝试使用C ++ 11中的线程库编写多线程软件。在互联网上找到的一些基本教程可以按预期编译和运行。但我自己的应用程序分成几个类总是抛出异常。

有人可以告诉我应该修复哪部分代码吗?

$ clang++ -std=c++11 -stdlib=libc++ BaseInterface.cxx -c -o BaseInterface.o
$ clang++ -std=c++11 -stdlib=libc++ SocketReceiver.cxx -c -o SocketReceiver.o
$ clang++ -std=c++11 -stdlib=libc++ main.cxx -c -o main.o
$ clang++ -std=c++11 -stdlib=libc++ main.o BaseInterface.o SocketReceiver.o -o main
$ gdb main  
(gdb) run
Starting program: /Users/oxon/test/main 
Reading symbols for shared libraries ++............................ done
libc++abi.dylib: terminate called throwing an exception

Program received signal SIGABRT, Aborted.
[Switching to process 859 thread 0x40b]
0x00007fff88df8212 in __pthread_kill ()
(gdb) bt
#0  0x00007fff88df8212 in __pthread_kill ()
#1  0x00007fff8bc85af4 in pthread_kill ()
#2  0x00007fff8bcc9dce in abort ()
#3  0x00007fff894d3a17 in abort_message ()
#4  0x00007fff894d13c6 in default_terminate ()
#5  0x00007fff89874887 in _objc_terminate ()
#6  0x00007fff894d13f5 in safe_handler_caller ()
#7  0x00007fff894d1450 in std::terminate ()
#8  0x00007fff894d25b7 in __cxa_throw ()
#9  0x00007fff8a9ba3b9 in std::__1::thread::join ()
#10 0x0000000100000cf0 in SocketReceiver::Receive ()
#11 0x0000000100000c6d in SocketReceiver::DoReceive ()
#12 0x0000000100001593 in _ZNSt3__114__thread_proxyINS_5tupleIJPFPvS2_ES2_EEEEES2_S2_ ()
#13 0x00007fff8bc84742 in _pthread_start ()
#14 0x00007fff8bc71181 in thread_start ()

这是OS X 10.8的结果。带有GCC 4.4的Scientific Linux 6也给出了类似的结果。

= BaseInterface.h =

#ifndef BASE_INTERFACE_H
#define BASE_INTERFACE_H

#include "SocketReceiver.h"

class BaseInterface
{
private:
  SocketReceiver*    fReceiver;

public:
  BaseInterface();
  virtual ~BaseInterface();

  virtual void Close();
  virtual void Open();
;

#endif

= BaseInterface.cxx =

#include <iostream>

#include <string.h>
#include <unistd.h>

#include "BaseInterface.h"

BaseInterface::BaseInterface()
{
  fReceiver = new SocketReceiver(this);
}

//______________________________________________________________________________
BaseInterface::~BaseInterface()
{
  Close();
  delete fReceiver;
  fReceiver = 0;
}

//______________________________________________________________________________
void BaseInterface::Close()
{
  fReceiver->Stop();
  usleep(10000);

  while(fReceiver->IsRunning()){
    usleep(10000);
  } // while
}

//______________________________________________________________________________
void BaseInterface::Open()
{
  fReceiver->Start();

}

= SocketReceiver.h =

#ifndef SOCKET_RECEIVER_H
#define SOCKET_RECEIVER_H

#include <thread>
#include <mutex>

class BaseInterface;

class SocketReceiver
{
private:
  BaseInterface*             fInterface;
  bool                       fIsRunning;
  std::mutex                 fMutex;
  bool                       fStop;
  std::thread*               fThread;

public:
  SocketReceiver(BaseInterface* interface = 0);
  virtual ~SocketReceiver();

  bool             IsRunning() const {return fThread ? true : false;}
  static void*     DoReceive(void* arg);
  void             Receive();
  void             Start();
  void             Stop();
};

#endif

= SocketReceiver.cxx =

#include <iostream>
#include <thread>
#include <unistd.h>

#include "BaseInterface.h"
#include "SocketReceiver.h"

SocketReceiver::SocketReceiver(BaseInterface* interface)
{
  fInterface = interface;
  fStop = true;
  fThread = 0;
}

//______________________________________________________________________________
SocketReceiver::~SocketReceiver()
{
}

//______________________________________________________________________________
void* SocketReceiver::DoReceive(void* arg)
{
  SocketReceiver* receiver = (SocketReceiver*)arg;
  receiver->Receive();

  return 0;
}

//______________________________________________________________________________
void SocketReceiver::Receive()
{
  while(not fStop){
    fMutex.lock();
    usleep(10000);
    fMutex.unlock();
  } // while

  fThread->join();

  delete fThread;
  fThread = 0;
}

//______________________________________________________________________________
void SocketReceiver::Start()
{
  fStop = false;
  fThread  = new std::thread(DoReceive, (void*)this);
}

//______________________________________________________________________________
void SocketReceiver::Stop()
{
  fStop = true;
}

= main.cxx =

#include "BaseInterface.h"

int main()
{
  BaseInterface interface;
  interface.Open();
  interface.Close();

  return 0;
}

2 个答案:

答案 0 :(得分:4)

你自己加入了这个主题。在主题中调用join,例如SocketReceiver::Stop

调用join时,它会清除基础数据。如果你在正在运行的线程中调用它,那么当线程仍需要它时,将删除该数据。

答案 1 :(得分:4)

如果std::thread运行的函数退出并且异常,则会调用std::terminate

如果在同一个线程中调用std::thread::join(),则指定

std::system_errorresource_deadlock_would_occur抛出错误代码join(),即线程无法自行加入。因此,尝试使线程自身连接会导致异常,从而终止进程。一个线程不能自己加入,加入被定义为“等待线程完成”所以显然不能由线程本身完成,它会阻止等待自己完成,这在调用{{1}之前不会发生}完成,直到线程完成才能发生,这在join()的调用结束之前不会发生......你能看到它的发展方向吗?

你为什么要这样做?

join()

fThread = new std::thread(DoReceive, (void*)this); 不是std::thread,您不需要传递pthread_create,只需删除void*并致电:

DoReceive

为什么fThread = new std::thread(&SocketReceiver::Receive, this); 分配了std::thread?这也没有必要,您可以使用new成员并使用std::thread检查它是否处于活动状态,而不是检查指针是否为非空。