如何从C#应用程序向BugTracker.NET提交错误?

时间:2009-10-05 18:17:44

标签: c# winforms bug-tracking winforms-to-web bugtracker.net

阅读BugTracker.NET的文档页面 BugTracker.NET API Documentation 我意识到我需要使用GET或POST,我不得不承认,我不是很擅长。我在想:

  • 是否有可用于从C#应用程序(或VB.NET)轻松向BugTracker.NET提交错误的库?
    或者,
  • 如果没有图书馆。如何使用GET或POST向BugTracker.NET提交错误?

4 个答案:

答案 0 :(得分:2)

查看如何使用.Net发出POST请求的简单示例from the documentation。只需确保根据BugTracker.NET API要求设置要POST的变量。

答案 1 :(得分:1)

以下是BugTracker.NET服务的代码,该服务从pop3服务器读取电子邮件,然后将其作为错误提交到insert_bug.aspx页面。但它不一定非常复杂。

只需调用此URL也可以:

http:\\YOUR-HOST\insert_bug.aspx?username=YOU&password=YOUR-PASSWORD&short_desc=This+is+a+bug

更复杂的代码:




            string post_data = "username=" + HttpUtility.UrlEncode(ServiceUsername)
                + "&password=" + HttpUtility.UrlEncode(ServicePassword)
                + "&projectid=" + Convert.ToString(projectid)
                + "&from=" + HttpUtility.UrlEncode(from)
                + "&short_desc=" + HttpUtility.UrlEncode(subject)
                + "&message=" + HttpUtility.UrlEncode(message);

            byte[] bytes = Encoding.UTF8.GetBytes(post_data);


            // send request to web server
            HttpWebResponse res = null;
            try
            {
                HttpWebRequest req = (HttpWebRequest) System.Net.WebRequest.Create(Url);


                req.Credentials = CredentialCache.DefaultCredentials;
                req.PreAuthenticate = true; 

                //req.Timeout = 200; // maybe?
                //req.KeepAlive = false; // maybe?

                req.Method = "POST";
                req.ContentType= "application/x-www-form-urlencoded";
                req.ContentLength=bytes.Length;
                Stream request_stream = req.GetRequestStream();
                request_stream.Write(bytes,0,bytes.Length);
                request_stream.Close();
                res = (HttpWebResponse) req.GetResponse();
            }
            catch (Exception e)
            {
                write_line("HttpWebRequest error url=" + Url);
                write_line(e);
            }

            // examine response

            if (res != null) {

                int http_status = (int) res.StatusCode;
                write_line (Convert.ToString(http_status));

                string http_response_header = res.Headers["BTNET"];
                res.Close();

                if (http_response_header != null)
                {
                    write_line (http_response_header);

                    // only delete message from pop3 server if we
                    // know we stored in on the web server ok
                    if (MessageInputFile == ""
                    && http_status == 200
                    && DeleteMessagesOnServer == "1"
                    && http_response_header.IndexOf("OK") == 0)
                    {
                        write_line ("sending POP3 command DELE");
                        write_line (client.DELE (message_number));
                    }
                }
                else
                {
                    write_line("BTNET HTTP header not found.  Skipping the delete of the email from the server.");
                    write_line("Incrementing total error count");
                    total_error_count++;
                }
            }
            else
            {
                write_line("No response from web server.  Skipping the delete of the email from the server.");
                write_line("Incrementing total error count");
                total_error_count++;
            }

答案 2 :(得分:0)

谢谢大家的回答。使用您在网络上的答案和其他资源,我总结了一种向BugTracker.NET提交新bug的方法 该方法返回一个表示成功或失败的布尔值,并向用户显示状态信息 可以更改此行为以满足您的需求。 该方法使用POST方法提交错误,这有助于在评论中提交任何长文本(我试图在评论中提交日志文件的内容并且它有效)。

以下是代码:

public bool SubmitBugToBugTracker(string serverName,
                                        bool useProxy,
                                        string proxyHost,
                                        int proxyPort,
                                        string userName,
                                        string password,
                                        string description,
                                        string comment,
                                        int projectId)
    {
        if (!serverName.EndsWith(@"/"))
        {
            serverName += @"/";
        }
        string requestUrl = serverName + "insert_bug.aspx";
        string requestMethod = "POST";
        string requestContentType = "application/x-www-form-urlencoded";
        string requestParameters = "username=" + userName
                                  + "&password=" + password
                                  + "&short_desc=" + description
                                  + "&comment=" + comment
                                  + "&projectid=" + projectId;
        // POST parameters (postvars)
        byte[] buffer = Encoding.ASCII.GetBytes(requestParameters);
        // Initialisation
        HttpWebRequest WebReq = (HttpWebRequest)WebRequest.Create(requestUrl);
        // Add proxy info if used.
        if (useProxy)
        {
            WebReq.Proxy = new WebProxy(proxyHost, proxyPort);
        }

        // Method is POST
        WebReq.Method = requestMethod;
        // ContentType, for the postvars.
        WebReq.ContentType = requestContentType;
        // Length of the buffer (postvars) is used as contentlength.
        WebReq.ContentLength = buffer.Length;
        // Open a stream for writing the postvars
        Stream PostData = WebReq.GetRequestStream();
        //Now we write, and afterwards, we close. Closing is always important!
        PostData.Write(buffer, 0, buffer.Length);
        PostData.Close();
        // Get the response handle, we have no true response yet!
        HttpWebResponse WebResp = (HttpWebResponse)WebReq.GetResponse();
        // Read the response (the string)
        Stream Answer = WebResp.GetResponseStream();
        StreamReader _Answer = new StreamReader(Answer);
        string responseStream = _Answer.ReadToEnd();

        // Find out if bug submission was successfull.
        if (responseStream.StartsWith("OK:"))
        {
            MessageBox.Show("Bug submitted successfully.");
            return true;
        }
        else if (responseStream.StartsWith("ERROR:"))
        {
            MessageBox.Show("Error occured. Bug hasn't been submitted.\nError Message: " + responseStream);
            return false;
        }
        else
        {
            MessageBox.Show("Error occured. Bug hasn't been submitted.\nError Message: " + responseStream);
            return false;
        }
    }

答案 3 :(得分:0)

我正在使用该方法,但不喜欢将密码与提交的错误一起发送。由于各种原因,我们使用的是内部BugTracker密码系统而不是LDAP身份验证,因此我们不知道他们的BugTracker密码。就我而言,我们的所有用户都有权提交错误,他们的登录名是他们的LAN ID。因此,从他们经过身份验证的应用程序实例中,我收集他们报告的问题,捕获他们报告问题的项目ID,程序和类,并调用BugTracker DB中的存储过程直接插入项目。

当然,消极的是,它直接进入数据库,可能会导致未来升级出现问题,但现在它对我们来说效果很好。

(SQL2005 / 2008)

CREATE PROCEDURE [dbo].[Add_Bug]
@strUsername as varchar(20) = '', 
@intProjID as integer = 0,
@strSubject as varchar(200),
@strComment as text
AS
    BEGIN
SET NOCOUNT ON;

declare @us_id as integer
declare @us_org as integer
declare @st_id as integer
declare @priority as integer
declare @category as integer
declare @errorreturn as integer
declare @assigneduser as integer

declare @newbugid as integer

if (@intProjID = 0 or RTRIM(@strUsername) = '') 
    RETURN -1

set @priority = 3 -- default to LOW
set @category = 1 -- default to bug

-- look up us_id, us_org from users where us_username = 'lanid'

set @us_id = 0

BEGIN TRY

    BEGIN TRANSACTION

    select @us_id = us_id, @us_org = us_org from BugTracker.dbo.users 
    where us_username = @strUsername

    if (@@ROWCOUNT = 0 or @us_id = 0 )
    BEGIN
        -- set to default values to allow entry anyway
        -- if not found default to the autobug reporter
                    -- this is a separate account created just for these reports
        set @us_id = 36     
        set @us_org = 6     
    END

    select @assigneduser = pj_default_user from projects 
                    where pj_id = @intProjID and 
        pj_auto_assign_default_user = 1

    if (@@ROWCOUNT <> 1)
        set @assigneduser = NULL

    -- get default status as st_id from statuses where st_default = 1

    select @st_id = st_id from BugTracker.dbo.statuses where st_default = 1 

    -- now insert the bug and post comments

    insert into bugs (bg_short_desc, bg_reported_user, bg_reported_date,
            bg_status, bg_priority, bg_org, bg_category, bg_project,                     
            bg_assigned_to_user, bg_last_updated_user, bg_last_updated_date) 
    values ( @strSubject, @us_id, getdate(), @st_id, @priority, @us_org,
            @category, @intProjID, @assigneduser, @us_id, getdate())

    if @@ERROR <> 0
        BEGIN
        ROLLBACK TRANSACTION
        END
    ELSE
        BEGIN

        select @newbugid = @@IDENTITY

        insert into bug_posts (bp_bug, bp_type, bp_user, bp_date,
                    bp_comment, bp_hidden_from_external_users)
        values (@newbugid, 'comment', @us_id, getdate(), @strComment, 0)

        if @@ERROR <> 0
            ROLLBACK TRANSACTION
        END
END TRY

BEGIN CATCH
    ROLLBACK TRANSACTION
    RETURN -2
END CATCH   

IF (@@TRANCOUNT > 0)
    COMMIT TRANSACTION

RETURN @newbugid

END