这是我当前的代码
function getUserDetails($username=NULL, $id=NULL) {
if($username!=NULL) {
$column = "user_name";
$data = $username;
}
elseif($id!=NULL) {
$column = "id";
$data = $id;
}
global $db;
$query = $db->prepare("SELECT id, username, permissions, forename, surname, password, email, courseid, choiceid, lastlogin, active FROM users WHERE $column = :column");
$query->bindParam(":column", $data);
$query->execute();
$query->bind_result ($id, $username, $permissions, $forename, $surname, $password, $email, $courseid, $choiceid, $lastlogin, $active);
while ($query->fetch()){
$row = array('id' => $id, 'userlevel' => $permissions, 'username' => $username, 'forename' => $forename, 'surname' => $surname, 'password' => $password, 'email' => $email, 'courseId' => $courseid, 'choiceId' => $choiceId, 'lastlogin' => $lastlogin, 'active'=> $active);
}
return ($row);
}
我一直在尝试将其转换为pdo,因为我发现bind_result不能与pdo一起使用 - 任何人都可以帮助我做我应该做的事情吗?
我已经阅读了我应该使用fetch的文章吗?但我真的很困惑。
[编辑]
我试过这个:
function getUserDetails($username=NULL,$id=NULL) {
if($username!=NULL) {
$column = "user_name";
$data = $username;
}
elseif($id!=NULL) {
$column = "id";
$data = $id;
}
global $db;
$query = $db->prepare("SELECT id, username, permissions, forename, surname, password, email, courseid, choiceid, lastlogin, active FROM users WHERE $column = :column");
$query->bindParam(":column", $data);
$query->execute();
$results = array();
while ($row = $query->fetch(PDO::FETCH_ASSOC)) {
$results[] = $row;
}
return ($results);
}
这是朝着正确方向迈出的一步吗?
[EDIT2]
将我的代码更新为:
function getUserDetails($username) {
global $db;
$query = $db->prepare("SELECT * FROM users WHERE username = :username");
$query->bindParam(":username", $username);
return $query->fetch(PDO::FETCH_ASSOC);
}
$username = 'uname';
$result = getUserDetails($username);
print_r($result);
然而它什么都没打印。用户名肯定存在。
我尝试过一些带有虚拟数据的测试数据库
$data = '2';
$sth = $db->prepare("SELECT * FROM test WHERE id = :id");
$sth->bindParam(":id", $data);
$sth->execute();
$result = $sth->fetch(PDO::FETCH_ASSOC);
print_r($result);
我试图找出我如何访问打印数组中的内容: 数组出来
Array ( [Id] => 2 [Name] => tom )
我(例如)如何做
$name = $result['name']; //line 67
当我尝试使用该代码时
Notice: Undefined index: name in <directory>\test.php on line 67
想出来了!
function getUserDetails($username) {
global $db;
$sth = $db->prepare("SELECT id, username, permissions, forename, surname, password, email, courseid, choiceid, lastlogin, active FROM users WHERE username = :username");
$sth->bindParam(":username", $username);
$sth->execute();
$result = $sth->fetch(PDO::FETCH_ASSOC);
return $result;
}
$username = 'un';
$userdetails = getUserDetails($username);
echo $userdetails['forename'];
它给了我正确的答案! 谢谢你的帮助
答案 0 :(得分:3)
YES!
这是朝着正确方向迈出的重要一步
正如您所看到的, mysqli绝对无法使用准备好的语句,在绑定占位符和中都会返回结果。
而PDO可以使用极少的代码来解决您的问题
您根本不需要与PDO无用绑定 - 只需使用fetchAll()获取所有结果:
function getUserDetails($username=NULL,$id=NULL) {
if ($username) {
$column = "user_name";
$data = $username;
} elseif($id) {
$column = "id";
$data = $id;
} else {
return;
}
global $db;
$query = $db->prepare("SELECT * FROM users WHERE $column = ?");
$query->execute(array($data));
return $query->fetchAll();
}
但是等等。如果是用户详细信息,为什么要返回数组? 它将为返回的数组添加无用的维度。 对于这种情况,请将其
return $query->fetch();
而不是fetchAll() 但是你需要很多行 - 使用后一种方法 有关其他方法和有用的连接选项,请参阅tag wiki