将mysqli转换为pdo bind_all

时间:2013-03-03 20:32:11

标签: php pdo mysqli

这是我当前的代码

function getUserDetails($username=NULL, $id=NULL) {
    if($username!=NULL) {
        $column = "user_name";
        $data = $username;
    }
    elseif($id!=NULL) {
        $column = "id";
        $data = $id;
    }

    global $db;

    $query = $db->prepare("SELECT id, username, permissions, forename, surname, password, email, courseid, choiceid, lastlogin, active FROM users WHERE $column = :column");
    $query->bindParam(":column", $data);
    $query->execute();
    $query->bind_result ($id, $username, $permissions, $forename, $surname, $password, $email, $courseid, $choiceid, $lastlogin, $active);
    while ($query->fetch()){
        $row = array('id' => $id, 'userlevel' => $permissions, 'username' => $username, 'forename' => $forename, 'surname' => $surname, 'password' => $password, 'email' => $email, 'courseId' => $courseid, 'choiceId' => $choiceId, 'lastlogin' => $lastlogin, 'active'=> $active);
    }
    return ($row);
}

我一直在尝试将其转换为pdo,因为我发现bind_result不能与pdo一起使用 - 任何人都可以帮助我做我应该做的事情吗?

我已经阅读了我应该使用fetch的文章吗?但我真的很困惑。

[编辑]

我试过这个:

function getUserDetails($username=NULL,$id=NULL) {
    if($username!=NULL) {
        $column = "user_name";
        $data = $username;
    }
    elseif($id!=NULL) {
        $column = "id";
        $data = $id;
    }

    global $db;

    $query = $db->prepare("SELECT id, username, permissions, forename, surname, password, email, courseid, choiceid, lastlogin, active FROM users WHERE $column = :column");
    $query->bindParam(":column", $data);
    $query->execute();

    $results = array();
    while ($row = $query->fetch(PDO::FETCH_ASSOC)) { 
        $results[] = $row;
    }

    return ($results);
}

这是朝着正确方向迈出的一步吗?

[EDIT2]

将我的代码更新为:

function getUserDetails($username) {
    global $db;

    $query = $db->prepare("SELECT * FROM users WHERE username = :username");
    $query->bindParam(":username", $username);
    return $query->fetch(PDO::FETCH_ASSOC);
}

$username = 'uname';
$result = getUserDetails($username);
print_r($result);

然而它什么都没打印。用户名肯定存在。


我尝试过一些带有虚拟数据的测试数据库

$data = '2';
$sth = $db->prepare("SELECT * FROM test WHERE id = :id");
$sth->bindParam(":id", $data);
$sth->execute();
$result = $sth->fetch(PDO::FETCH_ASSOC);
print_r($result);   

我试图找出我如何访问打印数组中的内容: 数组出来

Array ( [Id] => 2 [Name] => tom ) 

我(例如)如何做

$name = $result['name'];    //line 67

当我尝试使用该代码时

Notice: Undefined index: name in <directory>\test.php on line 67

想出来了!

function getUserDetails($username) {
    global $db;

    $sth = $db->prepare("SELECT id, username, permissions, forename, surname, password, email, courseid, choiceid, lastlogin, active FROM users WHERE username = :username");
    $sth->bindParam(":username", $username);
    $sth->execute();
    $result = $sth->fetch(PDO::FETCH_ASSOC);

    return $result;
}


$username = 'un';
$userdetails = getUserDetails($username);
echo $userdetails['forename'];

它给了我正确的答案! 谢谢你的帮助

1 个答案:

答案 0 :(得分:3)

YES!
这是朝着正确方向迈出的重要一步 正如您所看到的, mysqli绝对无法使用准备好的语句,在绑定占位符中都会返回结果。
而PDO可以使用极少的代码来解决您的问题 您根本不需要与PDO无用绑定 - 只需使用fetchAll()获取所有结果:

function getUserDetails($username=NULL,$id=NULL) {
    if ($username) {
        $column = "user_name";
        $data = $username;
    } elseif($id) {
        $column = "id";
        $data = $id;
    } else {
        return;
    }
    global $db;

    $query = $db->prepare("SELECT * FROM users WHERE $column = ?");
    $query->execute(array($data));
    return $query->fetchAll();
}

但是等等。如果是用户详细信息,为什么要返回数组? 它将为返回的数组添加无用的维度。 对于这种情况,请将其

    return $query->fetch();

而不是fetchAll() 但是你需要很多行 - 使用后一种方法 有关其他方法和有用的连接选项,请参阅tag wiki