我有以下代码似乎可行,用于在python中使用子进程将管道链接在一起,同时逐行读取/写入它们(不使用communicate()
预先)。代码只调用Unix命令(mycmd
),读取其输出,然后将其写入另一个Unix命令(next_cmd
)的stdin,并将最后一个命令的输出重定向到文件。
# some unix command that uses a pipe: command "a"
# writes to stdout and "b" reads it and writes to stdout
mycmd = "a | b"
mycmd_proc = subprocess.Popen(mycmd, shell=True,
stdin=sys.stdin,
stdout=subprocess.PIPE,
stderr=subprocess.PIPE)
# nextCmd reads from stdin, and I'm passing it mycmd's output
next_cmd = "nextCmd -stdin"
output_file = open(output_filename, "w")
next_proc = subprocess.Popen(next_cmd, shell=True,
stdin=subprocess.PIPE,
stdout=output_file)
for line in iter(mycmd.stdout.readline, ''):
# do something with line
# ...
# write it to next command
next_proc.stdin.write(line)
### If I wanted to call another command here that passes next_proc output
### line by line to another command, would I need
### to call next_proc.communicate() first?
next_proc.communicate()
output_file.close()
这似乎有效,并且只在命令末尾调用communicate()
。
我正在尝试扩展此代码以添加另一个命令,以便您可以执行以下操作:
mycmd1 | mycmd2 | mycmd3 > some_file
含义:逐行,从Python读取mycmd1的输出,进程该行,将其提供给mycmd2,读取mycmd2的输出并逐行处理和提要它到mycmd3,然后将其输出放在some_file
中。这是可能的,还是以死锁/阻塞/未刷新的缓冲区结束?请注意,我不只是将三个unix命令作为管道调用,因为我想在其间插入Python并逐行处理每个命令的输出,然后再将其提供给下一个命令。
我想避免调用通信并将所有输出加载到内存中 - 而是我想逐行解析它。感谢。
答案 0 :(得分:1)
这应该处理任意数量的命令:
import sys
import subprocess
def processFirst(out):
return out
def processSecond(out):
return out
def processThird(out):
return out
commands = [("a|b", processFirst), ("nextCmd -stdin", processSecond), ("thirdCmd", processThird)]
previous_output = None
for cmd,process_func in commands:
if previous_output is None:
stdin = sys.stdin
else:
stdin = subprocess.PIPE
proc = subprocess.Popen(cmd, shell=True,
stdin = stdin,
stdout = subprocess.PIPE)
if previous_output is not None:
proc.stdin.write(previous_output)
out,err = proc.communicate()
out = process_func(out)
previous_output = out
只需将要运行的任何命令添加到命令列表以及应处理其输出的函数。最后一个命令的输出最终将在循环结束时位于previous_output
。
为了避免任何死锁/缓冲/ etc问题,您只需使用proc.communicate()
运行每个命令即可完成,这将返回输出(而不是像您的示例中那样直接读取它)。然后在将其运行到完成之前将其提供给下一个命令,依此类推。
编辑:刚刚注意到您不想提前使用communicate()
并且您想要逐行做出反应。我会稍微编辑我的答案来解决这个问题
This answer提供了一个示例,说明如何使用select.select()
无阻塞地从管道逐行读取。
以下是针对您的特定情况使用它的示例:
import sys
import subprocess
import select
import os
class LineReader(object):
def __init__(self, fd, process_func):
self._fd = fd
self._buf = ''
self._process_func = process_func
self.next_proc = None
def fileno(self):
return self._fd
def readlines(self):
data = os.read(self._fd, 4096)
if not data:
# EOF
if self.next_proc is not None:
self.next_proc.stdin.close()
return None
self._buf += data
if '\n' not in data:
return []
tmp = self._buf.split('\n')
tmp_lines, self._buf = tmp[:-1], tmp[-1]
lines = []
for line in tmp_lines:
lines.append(self._process_func(line))
if self.next_proc is not None:
self.next_proc.stdin.write("%s\n" % lines[-1])
return lines
def processFirst(line):
return line
def processSecond(line):
return line
def processThird(line):
return line
commands = [("a|b", processFirst), ("nextCmd -stdin", processSecond), ("thirdCmd", processThird)]
readers = []
previous_reader = None
for cmd,process_func in commands:
if previous_reader is None:
stdin = sys.stdin
else:
stdin = subprocess.PIPE
proc = subprocess.Popen(cmd, shell=True,
stdin = stdin,
stdout = subprocess.PIPE)
if previous_reader is not None:
previous_reader.next_proc = proc
previous_reader = LineReader(proc.stdout.fileno(), process_func)
readers.append(previous_reader)
while readers:
ready,_,_ = select.select(readers, [], [], 10.0)
for stream in ready:
lines = stream.readlines()
if lines is None:
readers.remove(stream)