MYSQL查询适用于本周而非下一个

Question

SELECT a.agent, a.talktime, a.percentclosed,COALESCE(COUNT(b.dealamount),0),COALESCE(SUM(b.dealamount),0) , b.dealdate
FROM closers a
LEFT JOIN deals b ON a.agent = b.agent
WHERE b.dealdate IS NULL OR YEARWEEK( b.dealdate ) = YEARWEEK( NOW( ) ) 
GROUP BY a.agent
ORDER BY COALESCE( SUM( b.dealamount ) , 0 ) DESC 

任何人都可以帮我解决这个问题吗？我知道这个问题很乱，但我是新手，

这适用于本周，但如果我添加+1来模拟未来一周，那么前一周有交易的所有人都不会显示，

谢谢，

约翰，

查询的图像

Answer 1

WEEKOFYEAR在这种情况下并不好，因为它会在年底结束。你应该使用YEARWEEK（）。

WHERE b.dealdate IS NULL OR YEARWEEK( b.dealdate ) = YEARWEEK( NOW( ) ) +1

Answer 2

WHERE b.dealdate IS NULL OR WEEKOFYEAR( b.dealdate ) = WEEKOFYEAR( date_add(NOW( ), interval 1 week))

使用mysql的interval特性，以及date_add或date_sub函数

Reference

Answer 3

搞定了！，

SELECT a.agent, a.talktime, a.percentclosed, COALESCE( COUNT( b.dealamount ) , 0 )     ,COALESCE( SUM( b.dealamount ) , 0 ) , b.dealdate
FROM closers a
LEFT JOIN deals b ON a.agent = b.agent
AND WEEKOFYEAR( b.dealdate ) = WEEKOFYEAR( NOW( ) ) 
WHERE b.dealdate IS NULL 
OR WEEKOFYEAR( b.dealdate ) = WEEKOFYEAR( NOW( ) ) 
GROUP BY a.agent
ORDER BY COALESCE( SUM( b.dealamount ) , 0 ) DESC 
LIMIT 0 , 30